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Ad libitum [116K]
2 years ago
5

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20. Which state

ment is true of the box plot of this data set? The box will go from 10 to 12. A line dividing the box will be at 12. The left whisker will go from 4 to 15. The right whisker will go from 12 to 20.
Mathematics
2 answers:
ololo11 [35]2 years ago
8 0

Given:

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.

To find:

The correct statement for the box plot.

Solution:

Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15.

Median of the data set is 12, so a line dividing the box will be at 12.

Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.

Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.

Therefore, the correct option is B.

Gelneren [198K]2 years ago
5 0

Answer:

its b

Step-by-step explanation:

took the exam review

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Solve 4 + 4 ( x - 2 ) = 2 ( x + 1 ) - x<br> The question requires you to show your work
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Processing ends successfully

plz mark me as brainliest :)

7 0
3 years ago
Kiera used place value and the distributive property to find the product of 12 and 597. Her work is shown below. 12(597) = 12(50
olya-2409 [2.1K]

Answer:

(90)(7) ⇒ the error was multiplying 90 and 7.


Step-by-step explanation:

12(597) = 12(500 + 90 + 7)

            = 12(500) + (90)(7)

             = 6000 + 630

                = 6,630

The part in bold shows where the error is. It was not correct to multiply 90 and 7.

The process was to proceed as follows:

12(597) = 12(500 + 90 + 7)

            = 12(500) + 12(90) + 12(7)

             = 6000 + 1080 + 84

                = 7,164

8 0
2 years ago
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