When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)
Thus there are 11 total possible outcomes.
Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)
This means there are 7 outcomes with sum greater than or equal to 9.
Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11
So, option A gives the correct answer
Answer:
Can you clarify?
Step-by-step explanation:
Answer:
Step-by-step explanation:ghjhe
Answer:
A) segment AC ≅ segment DF
Step-by-step explanation:
You know AB = DE & BC = EF, so the only sides missing are AC = DF, so the answer is Side AC is congruent to side DF
Answer:
Step-by-step explanation:The formula is the long root of (x2-x1)² + (y2-y1)², you have -1 to be the value of x2 and -4 is the value of x1 while 4 is the value of y2 and -8 is the value of y1 therefore (-1+4)²+(4+8)² = (3)²+(12)²= √9+12=√153