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Ad libitum [116K]
3 years ago
5

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20. Which state

ment is true of the box plot of this data set? The box will go from 10 to 12. A line dividing the box will be at 12. The left whisker will go from 4 to 15. The right whisker will go from 12 to 20.
Mathematics
2 answers:
ololo11 [35]3 years ago
8 0

Given:

A data set has a median of 12, an upper quartile of 15, a lower quartile of 10, a minimum of 4, and a maximum of 20.

To find:

The correct statement for the box plot.

Solution:

Lower quartile is 10 and upper quartile is 15, so the box will go from 10 to 15.

Median of the data set is 12, so a line dividing the box will be at 12.

Minimum value is 4 and lower quartile is 10, so the left whisker will go from 4 to 10.

Upper quartile is 15 and maximum value is 20, so the right whisker will go from 15 to 20.

Therefore, the correct option is B.

Gelneren [198K]3 years ago
5 0

Answer:

its b

Step-by-step explanation:

took the exam review

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Answer:

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Step-by-step explanation:

<u>Given the following data;</u>

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Radius, r = \frac {diameter}{2}

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<em><u>Part A</u></em>

To find the area;

We know that a wheel is circular in nature. Thus, the area of a circle is given by the formula;

Area, A = \pi r^{2}

Substituting into the equation, we have;

Area, A = 3.14 * 5.5^{2}

Area, A = 3.14*30.25

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<em><u>Part B</u></em>

To find cost per square inch;

Cost \; per \; square \; inch = \frac {Cost \; per \; wheel}{Area \; of \; wheel}

Cost \; per \; square \; inch = \frac {21.35}{94.99}

<u>Cost per square inch = $0.23</u>

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3 years ago
How can 1/5x − 2 = 1/3x + 8 be set up as a system of equations? a . 5y − 5x = −10. 3y − 3x = 24 b. 5y − 5x = −10. 3y + 3x = 24 c
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The answer is d. 5y − x = −10. 3y − x = 24

\frac{1}{5}x-2=  \frac{1}{3}x+8=y
⇒   y= \frac{1}{5}x-2
      y= \frac{1}{3}x+8
________________________
y= \frac{x}{5} -2= \frac{x}{5} - \frac{10}{5} = \frac{x-10}{5}
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y= \frac{x-10}{5}            ⇒     5y=x-10
y= \frac{x+24}{3}           ⇒     3y=x+24
________________________
5y-x=-10
3y-x=24
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