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Vlad [161]
4 years ago
8

What kinds of asymptotes are possible for a rational function?

Mathematics
1 answer:
exis [7]4 years ago
7 0
Vertical or horizontal; it depends on what the function is.
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Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y
koban [17]

\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}

Substituting this into the other ODE gives

-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0

Since x(t)=-\dfrac14y'(t), it follows that x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16. The ODE in y has characteristic equation

r^2-16=0

with roots r=\pm4, admitting the characteristic solution

y_c=C_1e^{4t}+C_2e^{-4t}

From the initial conditions we get

y(0)=5\implies 5=C_1+C_2

y'(0)=16\implies-16=4C_1-4C_2

\implies C_1=\dfrac12,C_2=\dfrac92

So we have

\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}

Take the derivative and multiply it by -1/4 to get the solution for x(t):

-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}

7 0
4 years ago
Please Help Me :((.
Sidana [21]

Answer:

4.2 h

Step-by-step explanation:

12 * (50%-15%) = 4.2 h

8 0
3 years ago
Perimeter of a rectangle is 96m. if it's length is 3 times it's width , then find it's length and breadth.​
Stolb23 [73]

Answer:

breadth = 12

length = 36

Step-by-step explanation:

let the breadth be 'x'

length = 3x

p = 2l + 2b

96 = 2(3x) + 2(x)

x = 12

7 0
4 years ago
A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence
Step2247 [10]
The chance that any given bulb is on is equal to 1/2.  The chance that all twenty bulbs are on at the same time is (\frac{1}{2}) ^{20} = \frac{1^{20}}{2^{20}} = \frac{1}{1048576}
8 0
3 years ago
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What is the slope of the line?
avanturin [10]
3/4 To find the slope of a line you need to do rise/run. you find two solid points meaning find two points are exactly on a intersection. Then you count up how much it needs to the point then count across to the next point

8 0
3 years ago
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