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3 years ago

If x is 45% of y, then 110% of y is what percent

Mathematics

1 answer:

ch4aika [34]3 years ago

7 0

Answer:

c bro okkkkkkkkkkkkkkmmmmmmmkkkkkkkkkbey

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Let f(x)=x2+6x+11. What is the average rate of change from x = 5 to x = 8?

Korvikt [17]

Plug 8 into the equation and divide it by that equation but with 5 plugged in

$\frac{ {8}^{2} + 6(8) + 11}{ {5}^{2} + 6(5) + 11 }$

6 0

2 years ago

Read 2 more answers

Can someone explain why the answer is True. Will make brainliest.

MrRissso [65]

Answer:

True

Step-by-step explanation:

With Sin and Cos, the rule is that the opposites are the same:

SinA=CosB

CosB=SinA

In this problem, it is showing SinA=cosB, so it is the same, it is true.

Hope this helps!

8 0

2 years ago

Using the break apart method to find each product. What is the method for 5X5?

Ipatiy [6.2K]

I believe it is (2+2) × (3+3)

4 0

3 years ago

3. Let U and V be subspaces of a vector space W. Prove that their intersection UnV is also a subspace of W

kenny6666 [7]

Answer: The proof is done below.

Step-by-step explanation: Given that U and V are subspaces of a vector space W.

We are to prove that the intersection U ∩ V is also a subspace of W.

(a) Since U and V are subspaces of the vector space W, so we must have

0 ∈ U and 0 ∈ V.

Then, 0 ∈ U ∩ V.

That is, zero vector is in the intersection of U and V.

(b) Now, let x, y ∈ U ∩ V.

This implies that x ∈ U, x ∈ V, y ∈ U and y ∈ V.

Since U and V are subspaces of U and V, so we get

x + y ∈ U and x + y ∈ V.

This implies that x + y ∈ U ∩ V.

(c) Also, for a ∈ R (a real number), we have

ax ∈ U and ax ∈ V (since U and V are subspaces of W).

So, ax ∈ U∩ V.

Therefore, 0 ∈ U ∩ V and for x, y ∈ U ∩ V, a ∈ R, we have

x + y and ax ∈ U ∩ V.

Thus, U ∩ V is also a subspace of W.

Hence proved.

7 0

3 years ago

The parabola x = y² - 9 opens: a.)up b.)down c.) right d.)left

Zolol [24]

Answer:

Right side towards positive x axis

Step-by-step explanation:

Let us see the basic rule to find the orientation of parabolas.

1. If power if x is 2 and y is 1 , the parabola opens up or down.

2. If the power of y is 2 and that of x is 1 , the parabola opens right or left.

3. If the coefficient of $x^{2}$ in case 1 is negative it opens downward

4. If the coefficient of $y^{2}$ in case 2 is negative , it opens left towards negative x axis.

Hence our equation is

$x=y^2-9$

here is satisfies the case 2. hence it opens right or left . Also the coefficient of

$y^{2}$ is positive so it opens up to the right side , that is towards positive x axis.

7 0

2 years ago