Question

What is the product of d – 9 and 2d2 + 11d – 4?

Answer 1

Answer:

$2d^3-7d^2-103d+36$

A is the correct option.

Step-by-step explanation:

We have to find the product

$(d-9)(2d^2+11d-4)$

Using the distributive property (term by term multiplication), we have

$d\cdot2d^2+d\cdot11d+d\cdot(-4)-9\cdot2d^2-9\cdot11d-9\cdot(-4)$

On multiplying, we get

$2d^3+11d^2-4d-18d^2-99d+36$

Combine like terms

$2d^3-7d^2-103d+36$

A is the correct option.

Answer 2

Answer:

(A)$2d^3-7d^2-103d+36$

Step-by-step explanation:

It is given that there are two functions that are $(d-9)$ and $2d^2+11d-4$ and

We have to find the product of $(d-9)$ and $2d^2+11d-4$, therefore we can write as:

$(d-9)(2d^2+11d-4)$

$2d^3-18d^2+11d^2-99d-4d+36$

$2d^3-7d^2-103d+36$

which is the required product.

Thus, Option A is correct.