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2 years ago

(Lots of points)PLEASE HELP ME Due today at 8:59 in Texas

Mathematics

1 answer:

IceJOKER [234]2 years ago

6 0

Answer:

6.) So 8 of 24 hours is 1/3. So the percent of his time used was 33.33333 . . % (etc)

7.) The easiest way to figure out a percentage is dividing it. So if it was 30 hit out of 75 people, then divide 30 by 75. So 40% of them got hit.

Hope that helps

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Calculate the slope of a line

jeka94

M=-1/2 because you do y1-y2 over x1-x2 and end up with 2/-4 but simplified is -1/2

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2 years ago

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An airplane travels at a constant speed of 300 miles per hour. How far, in miles, will the airplane travel in 20 minutes?

Strike441 [17]

Answer:

100 miles in 20 minutes.

Step-by-step explanation:

300/60 = x/20

x = 300/60 * 20

x = 100

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2 years ago

Help on these precalc problems 14-20

Nadya [2.5K]

15) factor out cos: cos(x)(sin(x)+1)=0
Now this is true when either cos(x)=0 (x=pi/2 and 3pi/2)
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2 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Help guys I realy need help I will report you if you give me the wrong answer

telo118 [61]

Answer:

the Answer is 150x + 12100 ≤ 26500

Step-by-step explanation:

The max weight is 26500 so the weight would have to be the same or less than 26500 (≤)

There is already 12100 killograms on the sipping containter so that is why you have + 12100

and you have 150x because x is the number of 150-kilogram crates

and for as many crates you have to multiply by the weight.

7 0

2 years ago