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NemiM [27]
3 years ago
15

Why do i always hurt the people i love the most

Chemistry
2 answers:
tester [92]3 years ago
3 0

Answer:

Explanation:

i think when you love someone your brain might be relaxed and does not detected the stuff that was annoying to other thats what i think

Veronika [31]3 years ago
3 0

Answer:

You always hurt people you love the most

Explanation:

You always hurt people you love the most because you express your anger through anger without realizing this. When you are angry, you might feel like you want to explode at the whole world. During these times, you are feeling hurt. Sometimes you might even hurt others without realizing it, or you might hurt others intentionally. Instead of bottling up your anger or exploding at someone, you can express your anger productively. Calm yourself down and work on understanding your anger and other emotions. Then you can communicate your anger in an assertive manner that will be less likely to hurt the other person.

It might also be because you were being honest but was hurting them because they felt someway about you and they felt as if you never loved them back. People disagree about meaningful and trivial matters on a daily basis. Sometimes you know if you speak your mind you will upset someone. However, you often must express your opinion even if you know others will disagree. By choosing your words carefully you can avoid a long-term offense.

Sometimes, it can be because you never said you loved them and never asked them about what they think or never listened to them. If you want to help them without hurting them, you would have to put yourself in their shoes. Always control what you say and if it slipped out, try saying something good about what you said.

Express your perspective as opinion, not fact. Even if you know the facts back you up, this shows you value their perspective. If they have an open mind, facts will change their perspective. If they do not have an open mind, facts will feel like personal attacks. They have a right to be incorrect. Let them come to the truth on their own terms, not yours. Forcing your perspective is an easy way to hurt feelings.  

Don't take the disagreement personally. Keep in mind being honest is not the same as being right. You can be honest and factually wrong at the same time. You can also be honest, factually right, and still hurt feelings. Be humble with your perspective. Listen to others' justifications for their perspectives and resist the urge to convert them to your perspective.

Identify the source of the difference of opinion. Try to understand what your opinion is based on. Then try to understand what their opinion is based on. Some disagreements are based on fundamental political, religious, and moral beliefs. Knowing those bases you can be respectful of the opinion and avoid hurt feelings.

Pay attention to verbal and bodily cues. If the discussion is turning heated, stop. Chances are that you are about to hurt their feelings if you haven't already. Let them know you respect and value them.

Thank them for sharing and listening. This gives you an opportunity to end the difference of opinion on a positive note. Be sure to comment that you understand where they are coming from and hope they understand your perspective too.

Maybe you always had work and was never able to be around them. If you feel as if your job is taking up all your time, quit. Try doing something you love with them.

I've been through all of this. But, I made it work. You see, when people feel a type of way, they don't speak it.

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At what temperature is the following reaction feasible: HCl(g) + NH3(g) -> NH4Cl(s)?
Nutka1998 [239]
Energy is distributed not just in translational KE, but also in rotation, vibration and also distributed in electronic energy levels (if input great enough, bond breaks).

All four forms of energy are quantised and the quanta ‘gap’ differences increases from trans. KE ==> electronic.

Entropy (S) and energy distribution: The energy is distributed amongst the energy levels in the particles to maximise their entropy.

Entropy is a measure of both the way the particles are arranged AND the ways the quanta of energy can be arranged.

We can apply ΔSθsys/surr/tot ideas to chemical changes to test feasibility of a reaction:

ΔSθtot = ΔSθsys +  ΔSθsurr

ΔSθtot must be >=0 for a chemical change to be feasible.

For example: CaCO3(s) ==> CaO(s) + CO2(g) 

ΔSθsys = ΣSθproducts – ΣSθreactants 

ΔSθsys = SθCaO(s) + SθCO2(g) – SθCaCO3(s) 

ΔSθsurr is –ΔHθ/T(K) and ΔH is very endothermic (very +ve),

Now ΔSθsys is approximately constant with temperature and at room temperature the ΔSθsurr term is too negative for ΔSθtot to be plus overall.

But, as the temperature is raised, the ΔSθsurr term becomes less negative and eventually at about 800oCΔSθtot becomes plus overall (and ΔGθ becomes negative), so the decomposition is now chemically, and 'commercially' feasible in a lime kiln.

CaCO3(s) ==> CaO(s) + CO2(g)  ΔHθ = +179 kJ mol–1  (very endothermic)

This important industrial reaction for converting limestone (calcium carbonate) to lime (calcium oxide) has to be performed at high temperatures in a specially designed limekiln – which these days, basically consists of a huge rotating angled ceramic lined steel tube in which a mixture of limestone plus coal/coke/oil/gas? is fed in at one end and lime collected at the lower end. The mixture is ignited and excess air blasted through to burn the coal/coke and maintain a high operating temperature.
ΔSθsys = ΣSθproducts – ΣSθreactants
ΔSθsys = SθCaO(s) + SθCO2(g) – SθCaCO3(s) = (40.0) + (214.0) – (92.9) = +161.0 J mol–1 K–1
ΔSθsurr is –ΔHθ/T = –(179000/T)
ΔSθtot = ΔSθsys +  ΔSθsurr
ΔSθtot = (+161) + (–179000/T) = 161 – 179000/T
If we then substitute various values of T (in Kelvin) you can calculate when the reaction becomes feasible.
For T = 298K (room temperature)

ΔSθtot = 161 – 179000/298 = –439.7 J mol–1 K–1, no good, negative entropy change

For T = 500K (fairly high temperature for an industrial process)

ΔSθtot = 161 – 179000/500 = –197.0, still no good

For T = 1200K (limekiln temperature)

ΔSθtot = 161 – 179000/1200 = +11.8 J mol–1 K–1, definitely feasible, overall positive entropy change

Now assuming ΔSθsys is approximately constant with temperature change and at room temperature the ΔSθsurr term is too negative for ΔSθtot to be plus overall. But, as the temperature is raised, the ΔSθsurr term becomes less negative and eventually at about 800–900oC ΔSθtot becomes plus overall, so the decomposition is now chemically, and 'commercially' feasible in a lime kiln.
You can approach the problem in another more efficient way by solving the total entropy expression for T at the point when the total entropy change is zero. At this point calcium carbonate, calcium oxide and carbon dioxide are at equilibrium.
ΔSθtot–equilib = 0 = 161 – 179000/T, 179000/T = 161, T = 179000/161 = 1112 K

This means that 1112 K is the minimum temperature to get an economic yield. Well at first sight anyway. In fact because the carbon dioxide is swept away in the flue gases so an equilibrium is never truly attained so limestone continues to decompose even at lower temperatures.

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What two substances are always produced by a neutralization reaction?
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What two substances are always produced by a neutralization reaction? water and salt
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You are given solutions of hcl and naoh and must determine their concentrations. you use 27.5 ml of naoh to titrate 100.0 ml of
Dafna1 [17]
1) Start by standardizing the solution of NaOH by using the solution of H2SO4 whose concentration is known.

2) Equation:

2Na OH + H2SO4 --> Na2 SO4 + 2H2O

3) molar ratios

2 mol NaOH : 1 mol H2SO4

4) Number of moles of H2SO4 in 50.0 ml of 0.0782 M solution

M = n / V => n = M*V = 0.0782 M * 0.050 l = 0.00391 mol H2SO4

5) Number of moles of NaOH

2 moles NaOH / 1mol H2SO4 * 0.00391 mol H2SO4 = 0.00782 mol NaOH

6) Concentration of the solution of NaOH

M = n / V = 0.00782 mol / 0.0184 ml = 0.425 M

7) Standardize the solution of HCl

Chemical reaction:

NaOH + HCl --> NaCl + H2O

8) Molar ratios

1 mol NaOH : 1 mol HCl

9) Number of moles of NaOH in 27.5 ml

M = n / V => n = M * V = 0.425 M * 0.0275 l = 0.01169 moles NaOH

10) Number of moles of HCl

1 mol HCl / 1mol NaOH * 0.01169 mol NaOH = 0.01169 mol HCl

11) Concentration of the solution of HCl

M = n / V = 0.01169 mol / 0.100 l = 0.1169 M

Rounded to 3 significant figures = 0.117 M

Answers:

[NaOH] = 0.425 M
[HCl] = 0.117 M
3 0
3 years ago
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