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storchak [24]
3 years ago
8

How many electrons in the same atom can share the quantum number n = 3?

Chemistry
2 answers:
cricket20 [7]3 years ago
7 0

The answer is 18 o3o 3*6 = 18

Zepler [3.9K]3 years ago
4 0
Two electrons ...................
You might be interested in
If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?
laiz [17]

Answer:

164.3g of NaCl

Explanation:

Based on the chemical equation:

CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

<em>where 1 mole of CaCl2 reacts with 2 moles of NaOH</em>

To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

<em>Moles CaCl2 -Molar mass: 110.98g/mol-</em>

156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

<em>Moles NaCl:</em>

1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

<em>Mass NaCl -Molar mass: 58.44g/mol-</em>

2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

7 0
3 years ago
Help me now plssssssss i will give brainliest!!!!!!!!!!!!!!!!!!!!!!!
Blababa [14]
Products are copper+ aluminium chloride
reactants are aluminium+copper chloride
5 0
3 years ago
I NEED HELPPPP
Vinil7 [7]

Answer:

3 Handsprings

Explanation:

18 divided by 6 is 3

3 0
3 years ago
The equation for the formation of water from hydrogen gas and oxygen gas is 2H2+O2→2H2O.
inn [45]

Answer:

180g

Explanation:

H:1   O:16

2H2+O2 → 2H2O

 2   2(16)       2(1)+(16)

        32              18

Now,

       32g of O → 2(18)g of H2O

       160g of O → 2(18)g divides by 32g times 160g

                            =180g

5 0
3 years ago
Consider that calcium metal reacts with oxygen gas in the air to form calcium oxide. suppose we react 7.43 mol calcium with 4.00
Natali [406]
The balanced chemical equation for the above reaction is as follows;
2Ca + O₂ --> 2CaO
stoichiometry of Ca to O₂ is 2:1
this means that 2 mol of Ca reacts with 1 mol of O₂.
If O₂ is the limiting reactant, 
4 mol of O₂ should react with (4x2) - 8 mol of Ca
however only 7.43 mol of Ca is present. Therefore Ca is the limiting reactant.
7.43 mol of Ca reacts with - 7.43/2 = 3.715 mol of O₂
therefore there's excess O₂₂ remaining after the reaction
Since Ca is the limiting reactant, it is fully used up in the reaction and there is no Ca remaining after the reaction is completed.


4 0
3 years ago
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