Question

after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 22.0g of AgNO3(small 3) (molar mass=169.91 g/mol) were dissolved in water to a final solution volume of 725 mL, what is the molar concentration of this solution.

Answer 1

Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
 the number of the mol solute

$22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3 2) 725 ml = 0.725 L$

$3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725}$

$Molarity= \frac{0.178 mol}{L} , or 0.178 M$