after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2

Question

3 years ago

8

after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2

2.0g of AgNO3(small 3) (molar mass=169.91 g/mol) were dissolved in water to a final solution volume of 725 mL, what is the molar concentration of this solution.

Chemistry

1 answer:

Alexxandr [17] · Answer 1 · 2022-01-02T16:22:28+03:00

Alexxandr [17]3 years ago

3 0

Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
the number of the mol solute

$22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3

2) 725 ml = 0.725 L


$

$3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} 

$

$Molarity= \frac{0.178 mol}{L} , 

or 0.178 M
$