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Brilliant_brown [7]
3 years ago
8

after a chemistry student made a AgNO3(small 3 at bottom) solution., she wanted to determine the molar concentration of it. if 2

2.0g of AgNO3(small 3) (molar mass=169.91 g/mol) were dissolved in water to a final solution volume of 725 mL, what is the molar concentration of this solution.
Chemistry
1 answer:
Alexxandr [17]3 years ago
3 0
Molar concentration = (numbet of mol Solute)/ ( volume Solution)

1) Finding
 the number of the mol solute

22.0 g AgNO3 * \frac{1 mol AgNO3}{169.91 g AgNO3} = 0.129 mol AgNO3

2) 725 ml = 0.725 L




3) Molarity = \frac{number/ mol/solute}{Volume/solution} = \frac{0.129}{0.725} 



Molarity= \frac{0.178 mol}{L} , 

or 0.178 M



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