1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
professor190 [17]
3 years ago
7

Given: ΔABC, m∠C = 90º, m∠B = 30º CM - angle bisector Find: m∠AMC

Mathematics
1 answer:
SashulF [63]3 years ago
3 0

Answer:

75°

Step-by-step explanation:

1. Consider right triangle ABC. In this triangle

m∠C = 90º and CM - angle bisector.

If CM is angle C bisector, then

m∠ACM = m∠MCB = 45º

2. Consider triangle CMB. The sum of the measures of all interior angles of the triangle is always 180°, then

m∠MCB + m∠CBM + m∠BMC = 180°,

m∠BMC = 180° - 45° - 30°

m∠BMC = 105°

3. Angles AMC and BMC are supplementary angles, so

m∠AMC + m∠BMC = 180°

m∠AMC = 180° - 105°

m∠AMC = 75°

You might be interested in
Please help! I am supposed to write a recursive and an explicit function for the geometric sequence but this one is really frust
makkiz [27]

Step-by-step explanation:

Initially, there's only 1 letter.

Tania sends the letter to 4 friends.

Each friend sends a letter to 4 more friends (4 × 4 = 16).

Each of those friends sends to 4 more friends (16 × 4 = 64).

The pattern is 1, 4, 16, 64, etc.

This is a geometric sequence.  The first term is 1 and each term is 4 times the previous term.

a₁ = 1

aₙ = 4 aₙ₋₁

The explicit formula is:

aₙ = 1 (4)ⁿ⁻¹

7 0
3 years ago
An equation with a graph that is a straight line is called
Alinara [238K]
The answer is called a linear equation :))
7 0
2 years ago
Conner and Jana are multiplying (3⁵6⁸)(3⁹6¹⁰).
ad-work [718]
<h3>Conner work is correct. Jana work is wrong</h3>

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

<em><u>Conner and Jana are multiplying:</u></em>

(3^56^8)(3^96^{10})

Given Conner's work is:

(3^56^8)(3^96^{10}) = 3^{5+9}6^{8+10} = 3^{14}6^{18}

We have to check if this work is correct

Yes, Conner work is correct

From given,

(3^56^8)(3^96^{10})\\\\3^5 \times 6^8 \times 3^9 \times 6^{10}

Use the following law of exponent

a^m \times a^n = a^{m+n}

Therefore,

3^5 \times 6^8 \times 3^9 \times 6^{10} = 3^5 \times 3^9 \times 6^8 \times 6^{10} = 3^{5+9} \times 6^{8+10} = 3^{14} \times 6^{18}

<em><u>Given Jana's work is:</u></em>

(3^56^8)(3^96^{10}) = 3^{5.9}6^{8.10} = 3^{45}6^{80}

This is incorrect

The powers of same base has to be added. But here, powers are multiplied which is wrong

7 0
3 years ago
claudia bought a television at a 25% discount . the original price of the television was $349. there wasa 7% sales tax. how much
Scrat [10]
349 * .75 = $261.75
$261.75 * 1.07 = $280.07
6 0
2 years ago
...............2+2-2+2+2-4+2
kirill115 [55]

<em>Hi</em><em> </em><em>your</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>4</em><em>.</em><em>.</em>

<em>Please</em><em> </em><em>follow</em><em> </em><em>me</em><em>.</em><em>.</em>

8 0
3 years ago
Read 2 more answers
Other questions:
  • Jillian exercises 5 times a week she runs 3 miles each morning and bikes in the evening if she exercises a total of 30 miles for
    5·2 answers
  • If there was a circle and i wanted to find out the area.
    5·1 answer
  • A graph of quadratic function y = f(x) is shown below.
    13·2 answers
  • the grocery store sells kumquats for $4.50 a pound and asian pears for $3.75 a pound. write an equation in standard form for the
    11·1 answer
  • A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an even nu
    13·1 answer
  • 2.2⋅10^6−4.3⋅10^5<br> I need help I am confused on the answer.
    13·1 answer
  • Someone please help
    10·1 answer
  • How many lines of symmetry does the picture have?<br> PIC INCLUDED
    13·2 answers
  • Is 5 in the solution set of x + 3 &gt; 8? Explain
    14·1 answer
  • Help meeeeeeeeee pleaseee
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!