The ship sails at 20 km / h.
So
20 km / h x 2 h = 40 km
The boat moves 40 km to the northeast.
Then, in the same way:
20 km / h x 1 h = 20 km.
The ship moves 20 km northwest.
We solve this problem using vectors. In this case, we must perform the sum of two vectors a and b
a) magnitude = 40 km and direction 20 degrees east
b) magnitude = 20 km and direction 10 degrees northwest
In Cartesian coordinates, these vectors are written as:
a) 40sin (20º) i + 40cos (20º) j = 13,68i + 37,59j
b) -20sin (10th) i + 20cos (10th) j = -3,473i + 19,70j
The displacement vector of the ship would be the sum of a + b
a + b = 10,207i + 57,29j Finally, the magnitude of the a + b vector will tell us how far the ship is
√(10.21² + 57.29²) = 58.92km
Answer:
i may not have the explanition but its 21.35
TSplit into prime factors
1080 = 2*2*2*3*3*3*5
Its not a cube because although there are 2 triplicates there is also a 5.
Note 2*2*2*3*3*3 is a cube.
Answer:
The expected cost of the company for a 3000 tires batch is $120255
Step-by-step explanation:
Recall that given a probability of defective tires p, we can model the number of defective tires as a binomial random variable. For 3000 tires, if we have a probability p of having a defective tire, the expected number of defective tires is 3000p.
Let X be the number of defective tires. We can use the total expectation theorem, as follows: if there are 
events that partition the whole sample space, and we have a random variable X over the sample space, then
.
So, in this case, we have the following
.
Let Y be the number non defective tires. then X+Y = 3000. So Y = 3000-X. Then E(Y) = 3000-E(X). Then, E(Y) = 2949.
Finally, note that the cost of the batch would be 40Y+45X. Then
<span>D the weight of a bowling ball, which depends on the diameter of the ball, is 8.5 pounds.</span>
