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Y_Kistochka [10]
3 years ago
13

Find the start elapsed or end time

Mathematics
2 answers:
Nikolay [14]3 years ago
4 0
3:05 for question 10

But i cant really make out number 12.
Nesterboy [21]3 years ago
4 0
3:05 for your elapse end time
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What sine function represents an amplitude of 1, a period of 2π, a horizontal shift of π, and a vertical shift of −4?
Gwar [14]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\end{array}
\\\\
-------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad  \right. \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad  \right. \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)

with that template in mind, let's see

the period of 2π, well, for that, you have to do nothing, because that's sine original period

Amplitude of 1, well, that's also sine's original amplitude

horizontal shift/phase... ok, that means C/B = π, now, it doesn't say if to the left or the right, so I gather either is ok, so...let's do the right

you could use then, C = -π and B = 1, that gives you -π/1 or -π

vertical shift of -4, well, that simply means D = -4

f(θ) = sin(θ - π) - 4   <-- will do
5 0
4 years ago
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Anni [7]

Answer:

-1/3 is closer to 0

Step-by-step explanation:

3/8 is between 0 and -1/3. We need to determine if 3/8 is closer to -1/3 or closer to zero. Since -1/3 is smaller than 3/8, 3/8 is closer to -1/3. Since 3/8 is closer to -1/3, 3/8 rounded to the nearest -1/3 is -1/3.

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3 years ago
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Nady [450]
The problem can be solved by <span>proportion as following
</span>
<span>For every 15 columns of news stories in a newspaper, 4 columns of ads are required
</span>
If a newspaper contains 300 columns of news stories, x columns of ads are required
∴ 15 : 4 = 300 : x
∴ \frac{15}{4} =  \frac{300}{x}
By using cross multiplication
∴ 15 x = 4 * 300
∴ 15 x = 1,200
∴ x = 1,200/15 = 80

So, the number of <span>columns of ads must it have = 80 </span>
4 0
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lakkis [162]

Answer:


Step-by-step explanation:

So, she shared 4/5 of a bag of popcorn with Enrique...

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