All categories

3 years ago

Write the decimal -0.43 as a fraction in simplest form.

Mathematics

2 answers:

monitta3 years ago

7 0

-0.43= -43/100 I think this is correct I don’t know if it can be simplified

Vlad1618 [11]3 years ago

3 0

-43/100 I think, since 43 doesn’t have any factors other than 1 and itself

Hope this helps :)

You might be interested in

Determine if the card below represents a reflection over the x-axis or a

gtnhenbr [62]

Answer:

Reflection over y-axis

Step-by-step explanation:

We know that with a reflection of the x-axis, we flip the value of the y value

But since the y-values in Q3 and Q4 are both negative, we know that can't be the case

So it has to be a reflection over the y-axis where the x-values are flipped

Hope this helps

7 0

3 years ago

How do you add 3 fractions of different denominators

dimulka [17.4K]

Step 1: Find the Lowest Common Multiple between the denominators.

Step 2: Multiply the numerator and denominator of each fraction by a number (the one that will get them to the lcm) so that they have the LCM as their new denominator.

Step 3: Add or subtract the numerators and keep the denominator the same.

5 0

3 years ago

Read 2 more answers

3) Caleb's cellphone says that it is 20% charged. He has 45

ra1l [238]

Answer:

225 minutes

Step-by-step explanation:

45 min = 20% = 20/100

20 x 5 = 100

45 x 5 = 225

3 0

3 years ago

If an object is moving at a changing speed in the same direction what is the acceleration of the object (zero or not Zero)

andreyandreev [35.5K]

Answer:

zero

Step-by-step explanation:

hope its help thank you sa points

8 0

2 years ago

Read 2 more answers

Simplify <br> 1+sinx/cosx+cosx/1+sinx

Dmitry [639]

$\frac{1 + sin(x)}{cos(x)} + \frac{cos(x)}{1 + sin(x)}$
$\frac{[1 + sin(x)][1 +sin(x)]}{cos(x)[1 + sin(x)]} + \frac{cos(x)[cos(x)]}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x)}{cos(x)[1 + sin(x)]} + \frac{cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + sin^{2}(x) + cos^{2}(x)}{cos(x)[1 + sin(x)]}$
$\frac{1 + 2sin(x) + 1}{cos(x)[1 + sin(x)]}$
$\frac{1 + 1 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2 + 2sin(x)}{cos(x)[1 + sin(x)]}$
$\frac{2[1 + sin(x)]}{cos(x)[1 + sin(x)]}$
$\frac{2}{cos(x)}$
$2sec(x)$

6 0

3 years ago