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Dvinal [7]
3 years ago
5

Point I is on line segment HJ. Given HJ=15 and IJ=10, determine the length HI

Mathematics
2 answers:
Afina-wow [57]3 years ago
8 0

Answer:

Step-by-step explanation:

15 + 10 = 25

HI = 25

Arada [10]3 years ago
8 0

Answer: 5

Step-by-step explanation:

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AWARDED 40 POINTS Please help me
torisob [31]
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A= -24 • 2/3
A= 48/3
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20 • 0.2= -B
4= -B
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5 0
3 years ago
Finda + b, 2a + 3b, |a|, and |a − b|.a = 5i + j, b = i − 2j
expeople1 [14]

Answer:

Step-by-step explanation:

Given the complex notations a = 5i + j, b = i − 2j, we are to evaluate the following:

1) a + b

= 5i+j + (i-2j)

= 5i+j+i-2j

collect like terms

= 5i+i+j-2j

= 6i-j

<em>Hence a+b = 6i-j</em>

2) 2a+3b

= 2(5i+j) + 3(i-2j)

open the parenthesis

= 10i+2j+3i-6j

collect like terms

= 10i+3i+2j-6j

= 13i-4j

<em>Hence 2a+3b = 13i-4j</em>

3) |a| = √x²+y²

Given a = 5i+j; x = 5, y = 1

|a| = √5²+1²

|a| = √25+1

<em>|a| = √26</em>

4) |a-b|

First we need to calculate a-b

=  a - b

= 5i+j - (i-2j)

open the parenthesis

= 5i+j-i+2j

collect like terms

= 5i-i+j+2j

= 4i-3j

|a-b| = √4²+(-3)²

|a-b| = √16+9

|a-b| = √25

|a-b| = 5

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Fofino [41]

Answer:

264

Step-by-step explanation:

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3 years ago
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shtirl [24]
False. because the number before the decimal is a 0 on the first one and a 2 on the second, it is smaller.
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3 years ago
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