Write a program that asks for the names of three runners and the time, in minutes (no seconds, etc.), it took each of them to fi
nish a race. The program should display the names of the runners in the order that they finished. Note, assume there are no ties.
1 answer:
Answer:
Complete python code with explanation and output results is given below
Explanation:
User is asked to input names of runners and their finishing time
We have to determine first, second and third according to their finishing time.
if else conditioning is used to determine who has lowest finishing time.
Outer if is used to decide first position and inner if is used to decide second and third position.
str() function is used to concatenate the integer variable with string
Code:
runner1 = input("Please enter name of the runner1 ")
time1 = int(input("Please enter the time of runner1 "))
runner2 = input("Please enter name of the runner2 ")
time2 =int(input("Please Enter name of the runner2 "))
runner3 = input("Please enter name of the runner3 ")
time3 =int(input("Please Enter name of the runner3 "))
if(time1 < time2 and time1 < time3):
if(time2 < time3): // to decide 2nd and 3rd position
print(runner1+" has finished First with time: "+str(time1))
print(runner2+" has finished Second with time: "+str(time2))
print(runner3+" has finished Third with time: "+str(time3))
else:
print(runner1+" has finished First with time: "+str(time1))
print(runner3+" has finished Second with time: "+str(time3))
print(runner2+" has finished Third with time: "+str(time2))
if(time2 < time1 and time2 < time3):
if(time1 < time3):
print(runner2+" has finished First with time: "+str(time2))
print(runner1+" has finished Second with time: "+str(time1))
print(runner3+" has finished Third with time: "+str(time3))
else:
print(runner2+" has finished First with time: "+str(time2))
print(runner3+" has finished Second with time: "+str(time3))
print(runner1+" has finished Third with time: "+str(time1))
if(time3 < time1 and time3 < time2):
if(time2 < time1):
print(runner3+" has finished First with time: "+str(time3))
print(runner2+" has finished Second with time: "+str(time2))
print(runner1+" has finished Third with time: "+str(time1))
else:
print(runner3+" has finished First with time: "+str(time3))
print(runner1+" has finished Second with time: "+str(time1))
print(runner2+" has finished Third with time: "+str(time2))
Output:
Program has been tested with multiple inputs and results are accurate as per problem specifications.
Please enter name of the runner1 danny
Please enter the time of runner1 45
Please enter name of the runner2 sam
Please enter the time of runner2 34
Please Enter name of the runner3 tedd
Please enter the time of runner3 23
tedd has finished First with time: 23
sam has finished Second with time: 34
danny has finished Third with time: 45
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Answer:
Here is the JAVA program:
import java.util.Scanner; //to accept input from user
public class Main { // class name
public static void main(String [] args) { // start of main method
Scanner input = new Scanner(System.in); // creates Scanner class object to take input from user
System.out.println("Please Enter the Cost of the Item: "); // prompts user to enter the cost of item
double itemCost = input.nextDouble(); //scans and reads the input value of item cost
System.out.println("Please Enter the Amount Paid: "); // prompts user to enter the amount paid
double amount = input.nextDouble(); //scans and reads the value of amount from user
int change = (int)(amount * 100 - itemCost * 100); //compute the remaining amount i.e. change
System.out.println("Change Owed: " + change / 100.0); // displays the owed change
int quarters = change / 25; // computes the value for quarters
change = change % 25; // compute the quarters remaining
int dimes = change / 10; // computes dimes
change = change % 10; // computes dimes remaining
int nickels = change / 5; // computes nickels
change = change % 5; // compute nickels remaining
int pennies = change; // computes pennies
System.out.println("Quarters: " + quarters); // displays computed value of quarters
System.out.println("Dimes: " + dimes); // displays value of dimes
System.out.println("Nickels: " + nickels); // displays value of nickels
System.out.println("Pennies: " + pennies); }} //displays value of pennies
Explanation:
I will explain the program with an examples.
Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:
Change is computed as
change = (int)(amount * 100 - itemCost * 100);
This becomes;
change = (int)(5.00 * 100 - 4.57 * 100)
= 500 - 457
change = 43
Now the change owed is computed as:
change / 100.0 = 43/100.0 = 0.43
Hence change owed = 0.43
Next quarters are computed as:
quarters = change / 25;
This becomes:
quarters = 43/25
quarters = 1
Now the remaining is computed as:
change = change % 25;
This becomes:
change = 43 % 25;
change = 18
Next the dimes are computed from remaining value of change as:
dimes = change / 10;
dimes = 18 / 10
dimes = 1
Now the remaining is computed as:
change = change % 10;
This becomes:
change = 18 % 10
change = 8
Next the nickels are computed from remaining value of change as:
nickels = change / 5;
nickels = 8 / 5
nickels = 1
Now the remaining is computed as:
change = change % 5;
This becomes:
change = 8 % 5
change = 3
At last the pennies are computed as:
pennies = change;
pennies = 3
So the output of the entire program is:
Change Owed: 0.43 Quarters: 1 Dimes: 1 Nickels: 1 Pennies: 3
The screenshot of the output is attached.
