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Norma-Jean [14]
4 years ago
13

On other questions, how do I write my own question, without commenting on others questions? It is only allowed two, I think, the

n you have to comment on others. Please help.
Computers and Technology
1 answer:
faust18 [17]4 years ago
8 0
You go to whats your question and write your question
You might be interested in
A technician is installing RG6 cable and asks you to retrieve a connector from the parts drawer. What type of connector do you n
Bezzdna [24]

The type of connector, which is needed when a technician is installing RG6 cable and asks to retrieve a connector from the parts drawer, is F-connector.

<h3>What is F-connector?</h3>

The F-connector is a type of RF connector which is used to connect the Video equipments to the antennas and setup box.

A technician is installing RG6 cable.

  • The RG6 cable is a coax cable.
  • This cable is used in satellite signal transmission, generally for TV and setup box.

Now the technician is ask to retrieve a connector from the parts drawer. Here, we use F type connector for this RG6 cable.

Thus, the type of connector, which is needed when a technician is installing RG6 cable and asks to retrieve a connector from the parts drawer, is F-connector.

Learn more about the connector cable here

brainly.com/question/9082842

#SPJ1

4 0
2 years ago
When you pass an array to a method, the method receives ______.
7nadin3 [17]
The correct option is 3.
When an array is passed as a parameter to a function, it is usually passed as a reference parameter. What is actually passed is the address of its first element. Since arrays are typically passed by reference, it means that if the function changes the value of an element in an array, then the corresponding actual array will change that element. To declare an array of real values as parameter one has to specify the parameters.
4 0
3 years ago
Consider a sequence of method invocations as follows: main calls m1, m1 calls m2, m2 calls m3 and then m2 calls m4, m3 calls m5.
Minchanka [31]

Answer:

M2 is the answer for the above question.

Explanation:

  • The above question states the scenario, where firstly main function calls the M1 function.
  • Then M1 function calls the function M2.
  • Then M2 function calls the function M3.
  • Then M3 function calls the function M5.
  • Then Again M2 function will resume and calls the function M4.
  • Then Again M2 function will resume because when the M4 will ends it return to the statement of the M2 function from which the M4 function has been called.
  • It is because when any function ends its execution it returns to that line of a statement from which it has been called. This is the property of programming language to call the function.
  • So when the M4 will terminate its execution then the M2 function will resume again.
4 0
4 years ago
Brianna Watt, a consultant doing business as Watt Gives, wants a program to create an invoice for consulting services. Normally,
GREYUIT [131]

Answer:

The pseudocode is as follows:

Total_Hours = 0

Input Client_Name

Rate = 30.00

For days = 1 to 5

      Input Hours_worked

      Total_Hours = Total_Hours + Hours_Worked

Charges = Rate * Total_Hours

Print "Brianna Watt"

Print Client_Name

Print Total_Hours

Print Rate

Print Charges

Explanation:

This initializes the total hours worked to 0

Total_Hours = 0

This gets input for the client name

Input Client_Name

This initializes the standard rate to 30.00

Rate = 30.00

This iterates through the 5 days of work

For days = 1 to 5

This gets input for the hours worked each day

      Input Hours_worked

This calculates the total hours worked for the 5 days

      Total_Hours = Total_Hours + Hours_Worked

This calculates the total charges

Charges = Rate * Total_Hours

This prints the company name

Print "Brianna Watt"

This prints the client name

Print Client_Name

This prints the total hours worked

Print Total_Hours

This prints the standard rate

Print Rate

This prints the total charges

Print Charges

7 0
3 years ago
Assume a program requires the execution of 50 x 106 FP instructions, 110 x 106 INT instructions, 80 x 106 L/S instructions, and
Molodets [167]

Explanation:

FP - 50 \times 10^6

CPI - 1

INT -110 \times 10^6,

CPI - 1

I/S - 80 \times 10^6 ,

CPI - 4

Branch - 16 \times 10^6

CPI - 2

Clock Speed - 2 \times 10^9

Time(old) =\frac{50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)}{2 x 10^9}

Time(old) = 256 \times 10^ {-3}

Time(new) =  \frac{256 \times 10^{-3}}{2}

                = 128 \times 10^{-3}

                =\frac{CPI(new) x [50 x 10^6 + 110 x 10^6 + 4 x ( 80 x 10^6) + 2 x (16 x 10^ 6)]}{2 x 10^9}

                =  128 \times 10^{-3}

CPI(new) = \frac{-206}{50}

               = -4.12

3 0
3 years ago
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