15miles/1 hours = ?ft/1 hours

A family eats at a restaurant. The bill is $42. The family leaves a tip and spends $49.77.

jeka94

Answer;

7.77

Step-by-step explanation:

7 0

2 years ago

How many solution does 2x – 1 = 1 – 2x have?

ss7ja [257]

Answer:

1

Step-by-step explanation:

Hello,

2x – 1 = 1 – 2x

<=> 2x-1+2x=1

<=> 4x-1=1

<=> 4x = 1+1=2

<=> x = 2/4 = 1/2

Then there is only one solution.

Thanks

6 0

3 years ago

Read 2 more answers

To make the chocolate shake, Dona added 40 mL of chocolate syrup,

Vsevolod [243]

Answer:

0.225 L of milk, would be required if she uses 450 m L of water.

Step-by-step explanation:

Here, to make the shake, ingredients used by Dina are:

40 m L of chocolate syrup,

200 m L of milk, and 400 m L of water.

So, here Amount of water used = 2 x ( Amount of Milk used) ....... (1)

Now,again the amount of water used by Dona = 450 m L

Let us assume the milk used by her = k m L

⇒ 450 m L = 2 x ( k m L) ( from (1))

or, 450 = 2 k

⇒ k = 450/2 = 225

⇒ k = 225 m L

Also, 1 m L = 0.001 L

So, 225 m L = 225 x 0.001 = 0.225 L

⇒ k = 0.225 L

Hence, 0.225 L of milk, would be required if she uses 450 m L of water.

5 0

3 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

(c) $P(X > 980) = 0.00001\\\\$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$