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Ann [662]
3 years ago
6

5x - 3.3 = 7.2

Mathematics
1 answer:
zepelin [54]3 years ago
6 0

Answer:

A

Step-by-step explanation:

5x=10.5

x=2.1

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Find the slope: (-4, 3) and (8, -3)
olga2289 [7]

Answer:

-1/2

Step-by-step explanation:

The slope is the change in y over the change in x.

\frac{y_{2} -y_{1} }{x_{2} -x_{1} }

For this question:

\frac{3-(-3)}{-4-8} =\frac{6}{-12} =-\frac{1}{2}

4 0
3 years ago
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Which of these is NOT a terminating decimal?<br> A) 1.88<br> B) 1.875 <br> C) 0.88<br> D) 0.8
slamgirl [31]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
Allen�s hummingbird (Selasphorus sasin ) has been studied by zoologist Bill Alther A small group of 15 Allen� s hummingbirds has
Bogdan [553]

Answer:

1) 80% CI: [3.04; 3.26]gr

d= 0.11

2) n= 28 hummingbirds

Step-by-step explanation:

Hello!

The study variable of this experiment is:

X: the weight of a hummingbird. (gr)

And it has a normal distribution, symbolically: X~N(μ;σ²)

And (I hope I got it correctly) its population standard deviation is σ= 0.33

There was a sample of n= 15 hummingbirds taken, its sample mean X[bar]= 3.15 gr

1) You need to construct an 80% Confidence Interval for the population mean of the hummingbird's weight.

Since the study variable has a normal distribution, you can use either the standard normal distribution or the Student's t distribution. Both are useful to estimate the population mean. Since the population standard variance is known, the best choice is the Standard normal.

Z= <u> X[bar] - μ </u>~ N(0;1)

       σ/√n

The formula for the interval is:

X[bar] ± Z_{1- \alpha /2} * (σ/√n)

Z_{1- \alpha /2}= Z_{0.90} = 1.28

3.15 ± 1.28 * (0.33/√15)

[3.04; 3.26]gr

The margin of error (d) of a confidence interval is hal its amplitude (a)

a= Upper bond - Lower bond

d= (Upper bond - Lower bond)/2

d= \frac{(3.26-3.04)}{2} = 0.11

2) You need to calculate a sample size for a 80% Confidence interval for the average weight of the hummingbirds with a margin of error of d= 0.08

As I said before, the margin of error is half the amplitude of the interval, the formula you use to estimate the population mean has the following structure:

"point estamator" ± "margin of error"

Then the margin of error is:

d= Z_{1- \alpha /2} * (σ/√n)

Now what you have to do is rewrite the formula based on the sample size

d= Z_{1- \alpha /2} * (σ/√n)

\frac{d}{Z_{1- \alpha /2}}= σ/√n

√n * \frac{d}{Z_{1- \alpha /2}}= σ

√n = σ * \frac{Z_1- \alpha /2}{d}

n = (σ * \frac{Z_1- \alpha /2}{d})²

n=  (0.33 * \frac{1.28}{0.08})²

n= 27.8784 ≅ 28 hummingbirds.

I hope it helps!

4 0
3 years ago
Solutions to x^=-11x+4
anastassius [24]

x=-11x+4

x+11x=-11x+4+11x

12x=4

x= 4/12

<h2>Answer: x=1/3</h2>
5 0
3 years ago
Talib is trying to find the inverse of the function to the right. His work appears beneath it. Is his work correct? Explain your
Rasek [7]
To find the inverse of a function, we make the independent variable the subject of the formula.

Thus, the inverse of the given function is evaluated as follows.
f(x)=-8x+4 \\ y=-8x+4 \\ -8x=y-4 \\ x= \frac{y-4}{-8}  \\ f^{-1}(x)=\frac{x-4}{-8}

From the work show, it can be seen that Talib's work is correct.
4 0
3 years ago
Read 2 more answers
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