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Alecsey [184]
3 years ago
14

Hiro bought a small carton of milk at lunch. If the approximate dimensions of the milk carton are shown what is the minimum amou

nt of cardboard needed to make the milk carton? Round to the nearest whole number.
A. 65 in2
B. 95in2
C. 104in2
D.119in2

Mathematics
2 answers:
anyanavicka [17]3 years ago
8 0

Answer:

C) 104

Step-by-step explanation:

it was right on edu 2020

faltersainse [42]3 years ago
5 0

Answer:

C.\ 104\ in^2

Step-by-step explanation:

At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.

Let's calculate the front (and back) areas, which are rectangles

A_1=(6.5)(3)=19.5\ in^2

Now with the lateral rectangles which happen to have the very same dimensions

A_2=19.5\ in^2

Next, we compute the front and back triangles of base 3 in and height 1.5 in

A_3=\frac{1}{2}(3)(1.5)=2.25\ in^2

Now, the lateral inclined rectangles of base 3 in and height 2 in

A_4=(3)(2)=6\ in^2

Finally, the base rectangle who happens to be a square of side 3 in

A_5=(3)(3)= 9\ in^2

This last area, unlike all others, is not doubled because its counterpart is inside the carton and is not part of the lateral area

Our total area of cardboard is

A_t=2(19.5)+2(19.5)+2(2.25)+2(6)+9=103.5\ in^2

The closest option to this answer is

C.\ 104\ in^2

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