A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
136ft2 I did the work but I don't know if I understood the question correctly but maybe it is right lol
Answer:
, so using order of applications, it simplifies to 27+1.5+9 after multiplying and dividing, and the final answer is 37.5
Step-by-step explanation:
Answer:
The answer is 2
Step-by-step explanation:
If we use the formula for volume LWH=V. We also take in the fact that a cube has the same measure on every side. and we input 2 for L , W , and H
Which is 2*2*2=8
