Answer:
y = 2x² + 16x + 11
I hope im right... If not reaaally sorry!!
Answer:

Step-by-step explanation:
Given a circle centre J
Let the radius of the circle =r
LK is tangent to circle J at point K
From the diagram attached
Theorem: The angle between a tangent and a radius is 90 degrees.
By the theorem above, Triangle JLK forms a right triangle with LJ as the hypotenuse.
Using Pythagoras Theorem:

The length of the radius, 
Answer:
question 1: B
question 2: AB: 7 BC: 8 CD: 7 DA: 8
(pls mark brainliest)
Answer:
AB = x+ 8
Step-by-step explanation:
Given : QS=6x and CS=5x-8
From the given figure,
QS = QC + CS
We are given with QS and CS
Replace it the above equation
6x = QC + 5x -8
Solve for QC
Subtract 5x on both sides
x = QC + -8
Add 8 on both sodes
QC= x + 8
QABC is a rectangle
QC = AB
So AB = x+ 8
2 I think it is not sure hope it helps you out