Answer: ![=(0.2232,0.2768)](https://tex.z-dn.net/?f=%3D%280.2232%2C0.2768%29)
Step-by-step explanation:
The confidence interval for population proportion is given by :-
![p\ \pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}](https://tex.z-dn.net/?f=p%5C%20%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
Given : Sample size : ![n=1000](https://tex.z-dn.net/?f=n%3D1000)
The proportion of people selected consumers who had opportunities to send in a rebate claim form after purchasing a product said they never did so =![\dfrac{250}{1000}=0.25](https://tex.z-dn.net/?f=%5Cdfrac%7B250%7D%7B1000%7D%3D0.25)
Significance level : ![1-0.95=0.05](https://tex.z-dn.net/?f=1-0.95%3D0.05)
Critical value : ![z_{\alpha/2}=1.96](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3D1.96)
Now, the 95% confidence Interval for the true proportion of such consumers who never apply for a rebate will be :-
![0.25\ \pm (1.96)\sqrt{\dfrac{0.25(1-0.25)}{1000}}\\\\\approx0.25\pm0.0268\\\\=(0.2232,\ 0.2768)](https://tex.z-dn.net/?f=0.25%5C%20%5Cpm%20%281.96%29%5Csqrt%7B%5Cdfrac%7B0.25%281-0.25%29%7D%7B1000%7D%7D%5C%5C%5C%5C%5Capprox0.25%5Cpm0.0268%5C%5C%5C%5C%3D%280.2232%2C%5C%200.2768%29)
Hence, a confidence Interval for the true proportion of such consumers who never apply for a rebate .
Step-by-step explanation:
Si en cuatro vasos es un litro y cada integrante de la familia consume 2 litro diarios, la operacion seria 5 × 2 = 10 Por que son cinco integrantes de la familia y cada uno consume dos diarios entonces consumen 10 litro diarios
ESPERO Y TE AYUDE ;)
There’s 14 rolls. The probability he lands on a 2 would be 2/14. Once you simplify it it would give you a probability of 1/7