Answer:
Correct option is B.
The net benefit of the activity you would have chosen if you had not taken the course
Explanation:
Your opportunity cost of taking this course is <u>the net benefit of the activity you would have chosen if you had not taken the course
</u>
Opportunity cost is what you must sacrifice when you choose an activity. By taking this course, you are sacrificing the benefit you could have obtained from the activity you would have chosen if you had not taken the course.
The answer for this question would be
A) Rationing or the first option.
Answer:
The answer is true.
Explanation:
And increase or decrease in common stock or shareholders' equity is shown under statement of stockholders' equity.
It tells us the changes that happened from the beginning of the year till year ending.
It tells us how retained earnings decrease or increase, the dividend paid for the year, changes in common equity.
Po = 0.5385, Lq = 0.0593 boats, Wq = 0.5930 minutes, W = 6.5930 minutes.
<u>Explanation:</u>
The problem is that of Multiple-server Queuing Model.
Number of servers, M = 2.
Arrival rate, 
= 6 boats per hour.
Service rate, 
= 10 boats per hour.
Probability of zero boats in the system,![\mathrm{PO}=1 /\{[(1 / 0 !) \times(6 / 10) 0+(1 / 1 !) \times(6 / 10) 1]+[(6 / 10) 2 /(2 ! \times(1-(6 /(2 \times 10)))]\}](https://tex.z-dn.net/?f=%5Cmathrm%7BPO%7D%3D1%20%2F%5C%7B%5B%281%20%2F%200%20%21%29%20%5Ctimes%286%20%2F%2010%29%200%2B%281%20%2F%201%20%21%29%20%5Ctimes%286%20%2F%2010%29%201%5D%2B%5B%286%20%2F%2010%29%202%20%2F%282%20%21%20%5Ctimes%281-%286%20%2F%282%20%5Ctimes%2010%29%29%29%5D%5C%7D)
= 0.5385
<u>Average number of boats waiting in line for service:</u>
Lq =![[\lambda.\mu.( \lambda / \mu )M / {(M – 1)! (M. \mu – \lambda )2}] x P0](https://tex.z-dn.net/?f=%5B%5Clambda.%5Cmu.%28%20%5Clambda%20%2F%20%5Cmu%20%29M%20%2F%20%7B%28M%20%E2%80%93%201%29%21%20%28M.%20%5Cmu%20%E2%80%93%20%5Clambda%20%292%7D%5D%20x%20P0)
= ![[\{6 \times 10 \times(6 / 10) 2\} /\{(2-1) ! \times((2 \times 10)-6) 2\}] \times 0.5385](https://tex.z-dn.net/?f=%5B%5C%7B6%20%5Ctimes%2010%20%5Ctimes%286%20%2F%2010%29%202%5C%7D%20%2F%5C%7B%282-1%29%20%21%20%5Ctimes%28%282%20%5Ctimes%2010%29-6%29%202%5C%7D%5D%20%5Ctimes%200.5385)
= 0.0593 boats.
The average time a boat will spend waiting for service, Wq = 0.0593 divide by 6 = 0.009883 hours = 0.5930 minutes.
The average time a boat will spend at the dock, W = 0.009883 plus (1 divide 10) = 0.109883 hours = 6.5930 minutes.
In getting the GDP or Gross Domestic Product for year 1 and
year 2, you should multiply the price to the quantity of goods sold and add
them all up.
For GDP Year 1
Given:
Quarts of Ice Cream with a price of $6 and 4 quantity of
goods.
Bottle of Shampoo with a price of $5 and 2 quantity of
goods.
Jars of Peanut butter with a price of $3 and 4 quantity of
goods.
= (6 x 4) + (5 x 2) + (3 x 4)
= $46
For GDP Year 2, the same products with different price and
quantity.
= (6 x 6) + (5 x 3) + (3 x 3)
= $60
