Question

The total number of? restaurant-purchased meals that the average person will eat in a? restaurant, in a? car, or at home in a year is 163. The total number of these meals eaten in a car or at home exceeds the number eaten in a restaurant by 13. Twenty more? restaurant-purchased meals will be eaten in a restaurant than at home. Find the number of? restaurant-purchased meals eaten in a? restaurant, the number eaten in a? car, and the number eaten at home.

Answer 1

Answer:

The number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.

Step-by-step explanation:

Suppose, the number of meals eaten in a restaurant is $x$ , in a car is $y$ and at home is $z$

The total number of meals eaten in a restaurant, in a car or at home is given as 163. So, the first equation will be......

$x+y+z=163 .............................(1)$

The total number meals eaten in a car or at home exceeds the number eaten in a restaurant by 13. So, the second equation will be......

$y+z=x+13 ................................(2)$

Twenty more restaurant-purchased meals will be eaten in a restaurant than at home. So, the third equation will be......

$x= z+20..................................(3)$

First, substituting equation (2) into equation (1), we will get........

$x+(x+13)=163\\ \\ \Rightarrow 2x+13=163\\ \\ \Rightarrow 2x=163-13=150\\ \\ \Rightarrow x=\frac{150}{2}=75$

Now plugging this $x=75$ into equation (3), we will get......

$75=z+20\\ \\ \Rightarrow z=75-20= 55$

Plugging $x=75$ and $z=55$ into equation (1) .........

$75+y+55=163\\ \\ \Rightarrow y+130=163\\ \\ \Rightarrow y=163-130=33$

So, the number of restaurant-purchased meals eaten in a restaurant is 75, the number eaten in a car is 33 and the number eaten at home is 55.