y varies jointly as x and z, and y = 32 m, x = 6 m, and z = 8 m. What is the value of y when x = 5 m and z = 12 m
2 answers:
Answer:
y = 40
Step-by-step explanation:
If y varies jointly as x and z, the equation is
y = k* xz
We know y x and z so we can substitute them in
32 = k * 6*8
32 = k*48
Divide by 48
32/48 = k*48/48
32/48 =k
2/3 =
So the equation is y =2/3 x*z
Since we know x=5 and z =12, we can find y
y = 2/3 * 5 * 12
y = 40
We are given y = kxz
We also know 32 = k×6×8, so k = 32/48 = 2/3.
We are then asked to solve:
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Answer:
<h3>
41</h3>
Step-by-step explanation:
The consecutive integers are increasing by 1
x ← the smallest integer
x+1 ← the middle integer
x+1+1 = x+2 ← the largest integer
x + x+1 + x+2 = 120
3x + 3 = 120
÷3 ÷3
x + 1 = 40
-1 -1
x = 39
x+2 = 39 + 2 = 41
Y = 8x + 29 is the answer for your question
Answer:
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Answer:
geometric because it is decreased by 1/27
Step-by-step explanation:
These two lines have the same rate of change