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irina [24]
3 years ago
11

Can some help me please

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
8 0
Yes I can. Help you
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Which equation represents a line that passes through the two points in the<br> table?
ankoles [38]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
The diameter of a large lawn ornament in the shape of a sphere is 16 inches. What is the approximate volume of the ornament? Use
Dvinal [7]

Answer: 2143.6\ in.^3

Step-by-step explanation:

Given: The diameter of a large lawn ornament in the shape of a sphere = 16 inches.

Then, the radius of ornament =\frac{16}{2}=8 inches.

We know that the volume of a sphere is given by :-

\text{Volume}=\frac{4}{3}\pi r^3, where r is the radius of a sphere.

Now, the volume of the ornament is given by :-

\text{Volume}=\frac{4}{3}(3.14) (8)^3\\\\\Rightarrow\text{Volume}=\frac{4}{3}\times3.14\times512=2143.57333333\approx2143.6\ in,^3

Hence, the approximate volume of the ornament =2143.6\ in.^3

7 0
3 years ago
Read 2 more answers
Point x is located at (-2,-6) and point z is located at (0,5). Find the y value for the point y that is located 1/5 the disteanc
Sedaia [141]

Answer:

-3 1/2


Step-by-step explanation:

We have to find the distance between x and z along the y-axis.

This will be: 5 - -6 = 11 units

1/5  of 11 = 1/5 × 11

                 = 11/5

                 = 2 1/5

Now add 2.5 to -6

2 1/2 + -6 = -3 1/2

The value of y = -3 1/2

8 0
4 years ago
1)Circle 1 is centered at (−4, 5)(−4, 5) and has a radius of 2 centimeters. Circle 2 is centered at (2, 1)(2, 1) and has a radiu
galina1969 [7]

Figures of same shape and size are similar .Two circles  C1&C2 will be similar.

Circle 1 has a center of (-4,5) and circle 2 has a center of (2,1) .The x of the center is having the translation x+6 and the y  is having a translation of y-4.The center of the circle is dilated by 3 units.

The circles are similar because you can translate Circle 1 using the transformation rule (x+6,y-4 ) and then dilate it using a scale factor of 3.

2) Area of sector = \pi.r^{2}\alpha÷360.

Where α is the angle made at center.

Area of given sector= π(12)(12)(60)÷360 =24π.

8 0
3 years ago
Find the distance between the points given.
Maru [420]

Use the distance formula

d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2

Input corresponding numbers

d = \sqrt {\left( {2- 6} \right)^2 + \left( {5-8} \right)^2

Solve

d = \sqrt {\left( {-4} \right)^2 + \left( {-3} \right)^2

\sqrt{16 + 9}

\sqrt{25} = 5\\\\ d=5

So, the distance between the points given is 5

4 0
3 years ago
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