Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
For 2/5 cup, vanilla needed = 8 teaspoons
so, for 1 cup, it would be: 8 / 2/5
⇒8 × 5/2
⇒40/2
⇒20
In short, Your Answer would be 20 teaspoons
Hope this helps!
THE ANSWER TO THAT PROBLEM IS SIMPLY 175
Step-by-step explanation:
this is correct answer thank you
