The excluded values are x = 4 and x - 1
<h3>How to determine the excluded values?</h3>
The complete question is added as an attachment
The function is given as:
(2x^2 - 7x - 4)/(x^2 - 5x + 4)
Set the denominator to 0
x^2 - 5x + 4 = 0
Expand
x^2 - x - 4x + 4 = 0
Factorize the equation
x(x -1) - 4(x - 1) = 0
This gives
(x - 4)(x - 1) = 0
Solve for x
x = 4 and x - 1
Hence, the excluded values are x = 4 and x - 1
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Answer: x = -3
Step-by-step explanation:
-3x = 9
9 ÷ -3 = -3
:)
Answer:
the question you typed is wrong but that on the picture is correct and the correct table which satisfied the equation y =1/4x + 7 is table C
Answer:
Step-by-step explanation:
Im sorry!! i dont see a problem or any picture so i cant help :(
Answer:
The LCM, or least common multiple, of 6 and 8 is 24.