An irrational number, such as pi or the square root of 2
Answer:
yes they are
Step-by-step explanation:
hi!
1) rewrite as a fraction
(2^4/2^2)^3
2) reduce the expression by cancelling out the common factors
so factor out 2^2 out of 2^4
3) multiply by 1 so,
(2^2 * 2^2/ 2^2 * 1)^3
4) continue to cancel out common factors the rewrite the expression to be
(2^2/1)^3
5) then divide 2^2 by 1 so, it will be (2^2)^3
6) lastly simplify the expression so apply the power rule and multiply so it will be 2^2*3
then it will be 2^6
and raise 2 to the power of 6 and you answer is 64
Answer:
the answer is in the photo
Solution by completing the square.
-5x^2+20x-17
=-5(x^2-4x)-17
=(-5(x-2)^2+20) -17
=-5(x-2)^2+3
So a=-5, d=-2, e=+3
a+d+e=-5-2+3=-4