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2 years ago

Find an equation of the line satisfying the following conditions: Point (3,2);m= -5/6

Mathematics

1 answer:

Feliz [49]2 years ago

7 0

Answer:

Step-by-step explanation:

y -2 = -5/6(x -3)

y-2 = -5/6x + 15/6

y = -5/6x + 27/6

y = -5/6x + 9/2

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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?

Nonamiya [84]

Answer:

$\displaystyle \tan A=\frac{4}{3}$

Step-by-step explanation:

Funciones Trigonométricas

La identidad principal en trigonometría es:

$sen^2A+cos^2A=1$

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

$cos^2A=1-sen^2A$

Sustituyendo:

$\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2$

$\displaystyle cos^2A=1-\frac{16}{25}$

$\displaystyle cos^2A=\frac{25-16}{25}$

$\displaystyle cos^2A=\frac{9}{25}$

Tomando raíz cuadrada:

$\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}$

La tangente se define como:

$\displaystyle \tan A=\frac{sen\ A}{cos\ A}$

Substituyendo:

$\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}$

$\displaystyle \tan A=\frac{4}{3}$

6 0

2 years ago

Vectors... Let u = <-3, -5>, v = <-3, 1>. Find u + v.

Anni [7]

-3 + -3 = 0
-5 + 1 = -4
vector = < 0,-4 >

3 0

2 years ago

What is the circumference of the circle if r = 3.5 feet? Use 22 7 for π.45 pts

Natasha_Volkova [10]

We know, Circumference of a Circle = 2πr
C = 2 * 22/7 * 3.5
C = 2 * 22/2
C = 2 * 11
C= 22

In short, Your Answer would be 22 Feet

Hope this helps!

6 0

2 years ago

Read 2 more answers

Statistics how do we determine a percentage

givi [52]

Percent simply means "per hundred" and the symbol used to express percentage is %. One percent (or 1%) is one hundredth of the total or whole and is thereforecalculated by dividing the total or whole number by 100. To calculate the percentagedifference between two numbers, the same basic calculations are used

7 0

3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable X represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

2 years ago