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Nostrana [21]
3 years ago
8

Ms. brown's class will raise rabbits for their spring science fair. they have 24 feet of fencing with which to build a rectangul

ar rabbit pen in which to keep the rabbits. if ms. brown's students want their rabbits to have as much room as possible, how long would each of the sides of the pen be?how long would each of the sides of the pen be if they had only 16 feet of fencing?
Mathematics
1 answer:
telo118 [61]3 years ago
7 0
Each side of the fence should have 6 feet if they have 24 feet and if they have 16 feet then each side will be 4 feet long.
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63/10 equivalent mixed number
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Suppose you need to get the dent in your car fixed. You see the ads in the newspaper above (mikes repair shop $100 service charg
Norma-Jean [14]

Answer:

<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295, so I will take the car to Amy's shop</em>

<em>Point of intersection: (x,y) = (4,360)</em>

Explanation:

Part 1 )

Let x = number of hours worked

Let y = total cost to you

Determining where to take the car:

<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295</em>

Mike's repair shop:

Service fee: $100

Per hour rate: $65

Let x is the number of hours worked on. Total cost will be equal to the service fee plus hourly charges. Charges per an hour are $65, so for x hours the charges will be 65x.

Therefore, total cost for Amy's repair shop can be written as:

y = 100 + 65x ------(1)

For 3 hours work: y = 100 + 65(3)

<em>Cost at Mike's, y = $100 + $195 = $295</em>


<em>Amy's repair shop: </em>

Service fee: $40

Per hour rate: $80

Charges per an hour are $40, so for x hours the charges will be 80x.

Therefore, total cost for Amy's repair shop can be written as:

y = 40 + 80x ------(2)

For 3 hours work: x = 3

y = 40 + 80(3)

<em>Cost at Amy's, y  = $40 + $240 = $280</em>


<em>Part 2)</em>

<em>Find the point of intersection</em>

<em>Using elimination method:</em>

<em>y = 100 + 65 x    ------1</em>

<em>y = 40 + 80x      ------2</em>

<em>As the y coefficients are equal we will subtract eq1 from eq2</em>

<em>y - y = 40 + 80x - 100 - 65x</em>

<em>0 = -60 + 15x</em>

60 = 15x

x = \frac{60}{4}

x = 4

put x = 4 in eq 1

we get y = 100 + 65 (4) = 100 + 260 = 360

x = 4, y = 360

Point of intersection: (x,y) = (4,360)



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