Using p1v1/t1=p2v2/t2
p1=175kpa
p2=215kpa
v1=19l
v2=?
t1=25+273=298
t2=30+273=303
175x19/298=215xv2/303
8.808x303=215v2
2669/215=v2
v2=12.4l
Answer:
∴ The absolute pressure of the air in the balloon in kPa = 102.69 kPa.
Explanation:
- We can solve this problem using the general gas law:
<em>PV = nRT</em>, where,
P is the pressure of the gas <em>(atm)</em>,
V is the volume of the gas in L <em>(V of air = 6.23 L)</em>,
n is the no. of moles of gas <em>(n of air = 0.25 mole)</em>,
R is the general gas constant <em>(R = 0.082 L.atm/mol.K)</em>,
T is the temperature of gas in K <em>(T = 35 °C + 273 = 308 K</em>).
∴ P = nRT / V = (0.25 mole)(0.082 L.atm/mol.K)(308 K) / (6.23 L) = 1.0135 atm.
- <em>Now, we should convert the pressure from (atm) to (kPa).</em>
1.0 atm → 101.325 kPa,
1.0135 atm → ??? kPa.
∴ The absolute pressure of the air in the balloon in kPa = (101.325 kPa)(1.0135 atm) / (1.0 atm) = 102.69 kPa.
Answer:
13
Explanation:
Let's consider the unbalanced equation for the combustion of propane.
C₃H₈ + O₂ ⇒ CO₂ + H₂O
We will begin balancing H atoms by multiplying H₂O by 4.
C₃H₈ + O₂ ⇒ CO₂ + 4 H₂O
Now, we balance C atoms by multiplying CO₂ by 3.
C₃H₈ + O₂ ⇒ 3 CO₂ + 4 H₂O
Finally, we get the balanced equation multiplying O₂ by 5.
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
The sum of the coefficients is 1 + 5 + 3 + 4 = 13.
A wind vane is an instrument that determines the direction from which the wind is blowing