2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
<span>choices are:
Zirconium metal plus hydrogen chloride yields zirconium chloride solution and hydrogen gas
Xenon solid plus hydrochloric acid yields xenon chloride and hydrogen gas
Zinc metal plus hydrogen chloride yields zinc dichloride plus hydrogen gas
Zinc metal plus an aqueous solution of hydrochloric acid yields an aqueous solution of zinc chloride plus hydrogen gas
right ans is:
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Zinc metal plus an aqueous solution of hydrochloric acid yields an aqueous solution of zinc chloride plus hydrogen gas<span>
</span>
Answer:
Nitrate is considered SOLUBLE
Explanation:
please kindly refer to attachment for the step by step solution of the given problem.
