If you are looking for the equation of the line,
Use Point Slope Form
y-4 = 3(x-1)
y-4 = 3x-3
y = 3x + 1
Answer:
This cannot be solved but it can be simplified
first we open the bracket
so we have
a²- abx/x = 2/3
next we cross multiply so it will be 3(a² - abx) = 2x
we get
3a² - 3abx = 2x
Next we factorise so we can get
3a(a-bx) =2x
I dont know what exactly you where asked but I hop this helps
Answer:
The slope for this equation is .
Step-by-step explanation:
x y
point 1: -4 -3
point 2: 3 -2
slope:
To solve for slope here is an equation, to help:
Answer: 12
Step-by-step explanation: you would divide the interest by the amount of time. 60/5
Answer:
titutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
1
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