Answer:
y = 1/2
x = -1 / 3
z = -3
Step-by-step explanation:
In this question, in order to find "y" and "x", we do the following...
Since we know z = -3 we can find "y" by substituting z in the second equation.
2y + 3z = -8
2y + 3(-3) = -8
2y - 9 = -8
2y = 1
Now we know "y" and "z" and so we can find x...
3x + 4y + z = -2
3x + 4(1/2) - 3 = -2
3x + 2 - 3 = -2
3x = -1
z=-3 so 2y+3(-3)=-8, 2y-9=-8, add 9 to both sides 2y=1 divide both sides by 2, y=1/2, so 3x+4(1/2)+-3=-2, 3x+2-3=-2, 3x-1=-2, add 1 to both sides, 3x=-1, divide both sides by 3, x=-1/3
{[12 ÷ 4] + [16 ÷ 8 (7 – 5)]} – 1.
{[3] + [2(2)]} – 1.
{[3] + [4]} – 1.
7-1
6
<em><u>Solution:</u></em>
<em><u>Given equation is:</u></em>
6x + 5 = 12 + 5x
Try the numbers 4, 5, 6, 7 in the equation to test whether any of them is a solution
<em><u>Substitute x = 4</u></em>
6(4) + 5 = 12 + 5(4)
24 +5 = 12 + 20
Thus 4 is not a solution
<em><u>Substitute x = 5</u></em>
6(5) + 5 = 12 + 5(5)
30 + 5 = 12 + 25
Thus 5 is not a solution
<em><u>Substitute x = 6</u></em>
6(6) + 5 = 12 + 5(6)
36 + 5 = 12 + 30
Thus 6 is not a solution
<em><u>Substitute x = 7</u></em>
6(7) + 5 = 12 + 5(7)
42 + 5 = 12 + 35
47 = 47
Thus 6 is a solution
X= 130°
From E, draw EF || AB || CD.
Now, EF || CD and CE is the transversal.
So; <DCE + <CEF = 180° [co. int. <s]
x° + <CEF = 180°
<CEF = (180° – x°).
Again, EF || AB and AE is the transversal.
So; <BAE + <AEF = 180° 01 [co. int. <s ]
105° + <AEC+ <CEF = 180°
105° +25° + (180° – x°) = 180°
x° = 130°
I hope I helped you^_^
naruto and the square root to 1 is 1