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4 years ago

Whats the midpoint of (3,-8) and (5,-2.5)

Mathematics

1 answer:

Arte-miy333 [17]4 years ago

4 0

(4, -5.25) ................

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Helppp pls very urgent

Ludmilka [50]

Answer:

1. 22000 millimeters

2. 1.5 grams

3. 15 centigrams

4. 5300 milliliters

5. 0.025 decagrams

6. 0.0083 decimeters

7. 0.027 decaliters

8. 28.7 millimeters

9. 5.4 decigrams

10. 1000 milligrams

Step-by-step explanation:

6 0

3 years ago

Find the area of the rhombus please or teach me how to find the area

nevsk [136]

A=pq divided by 2.
I hoped this helped a little

3 0

3 years ago

Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!

vekshin1

Answer:

2. 3.913 kg (3 dp)

3. light cream

4. 240 CoffeeStops

5. 7 CoffeeStops per square mile

6. 2,861 cups of coffee each day

Step-by-step explanation:

Given:

Skim milk density at 20 °C = 1.033 kg/l
Light cream density at 20 °C = 1.012 kg/l
1 liter = 0.264 gallons

Question 2

$\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}$

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

Question 3

Given:

Volume of liquid = 9 liters
Mass of liquid = 9.108 kg

$\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}$

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

Question 4

Given:

15 CoffeeStops per 100,000 people
Population of Manhattan ≈ 1,602,000 people

$\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}$

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

Question 5

Given

Manhattan ≈ 34 square miles

$\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}$

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

Question 6

Given:

Each person buys 3 cups of coffee per week

$\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}$

$\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}$

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0

2 years ago

Omar went to a Chicago Cubs game and purchased 1 pound of peanuts for $1.29. How much would 7 pounds of peanuts cost?

viktelen [127]

Answer:

$9.03

Step-by-step explanation:

if one pound of peanuts cost $1.29

and you want to know how much 7 pounds costs, you multiply $1.29 by 7.

$1.29×7=$9.03

3 0

3 years ago

Based on the sample of 500 people, 42% owned cats. Calculate the test statistic. Round to two decimal places.

Tanzania [10]

Answer:

z= 3.63

z for significance level = 0.05 is ± 1.645

Step-by-step explanation:

Here p = 42% = 0.42

n= 500

We formulate our null and alternative hypotheses as

H0: p= 0.42 against Ha : p> 0.42 One tailed test

From this we can find q which is equal to 1-p= 1-0.42 = 0.58

Taking p`= 0.5

Now using the z test

z= p`- p/ √p(1-p)/n

Putting the values

z= 0.5- 0.42/ √0.42*0.58/500

z= 0.5- 0.42/ 0.0220

z= 3.63

For one tailed test the value of z for significance level = 0.05 is ± 1.645

Since the calculated value does not fall in the critical region we reject our null hypothesis and accept the alternative hypothesis that more than 42% people owned cats.

4 0

3 years ago