HELPPPPPPPPPPPPPPPPpppp
1 answer:
You might be interested in
Answer:
The quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.
Step-by-step explanation:
Given: Coffee costing $4 a pound is mixed with 3 pounds of coffee costing 4.50 a pound to obtain a mixture costing $4.30 a pound.
We have to find the quantity of coffee costing $4 a pound in the mixture.
Let x represent the number of pounds of $4 coffee.
Cost of one pound = 4x.
Cost of 3 pounds of coffee costing 4.50 a pound = 3(4.50)
Cost of mixture costing $4.30 a pound = (x+3)(4.30)
According to given problem,
Solving for x, we get,
Rearranging like term together, we get,
Thus, the quantity of coffee costing $4 a pound in the coffee mixture is 2 pounds.
Let x represent the number
.. 1 +3x . . . . . . one more than three times a number
.. x -5 . . . . . . . the number decreased by 5
.. 1 +3x < x -5 . . . . the relation specified by the problem statement
.. 2x < -6 . . . . . . . subtract x+1
.. x < -3 . . . . . . . . . divide by the coefficient of x. (Positive, so < stays the same.)
.. 1 +3x . . . . . . one more than three times a number
.. x -5 . . . . . . . the number decreased by 5
.. 1 +3x < x -5 . . . . the relation specified by the problem statement
.. 2x < -6 . . . . . . . subtract x+1
.. x < -3 . . . . . . . . . divide by the coefficient of x. (Positive, so < stays the same.)