Answer: $9
Step-by-step explanation:
Let the cost for adults be a
Let the cost for students be b.
The first van transported 2 adults and 5 students and cost $77. This will be:
2a + 5b = $77
The second van transported 2 adults and 7 students and cost $95. This will be:
2a + 7b = $95
2a + 5b = 77 ...... equation i
2a + 7b = 95 ........ equation ii
Subtract equation ii from I
-2b = -18
b = 18/2
b = $9
An student cost $9
Put the value of b into equation i
2a + 5b = 77
2a + 5(9) = 77
2a + 45 = 77
2a = 77 - 45
2a = 32
a = 32/2
a = 16
An adult costs $16
The distance between city C and city D is 450 miles.
<u>Solution:</u>
Given, The distance between City A and City B is 250 miles.
A length of 2.3 feet represents this distance on a certain wall map.
City C and City D are 4.14 feet apart on this map.
We have to find what is the actual distance between City C and City D?
Now, distance between a and b is 250 miles ⇒ 2.3 feet on map
Then, distance between c and d be n miles ⇒ 4.14 feet on map.
Now, by chris cross method.
250 x 4.14 = 2.3 x n miles.
2.3n = 1035
n = 450
Hence, the distance between city C and city D is 450 miles.
Answer:
\frac{15a+20b}{6} 15a+20b/6
Step-by-step explanation:
\mathrm{Apply\:the\:fraction\:rule}:\quad \:a\cdot \frac{b}{c}=\frac{a\cdot \:b}{c}
AE is about half of AC. What I did was get half of 28, which is 14, and represented one of the numbers.
3 x 7 = 21 - 7 = 14
It is D.
(I don't know for sure if this is right, but I did the best I could)
