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3 years ago

Is the distance that you walk equal to the magnitude of your displacement

1 answer:

7 0

Magnitude is basically the measurement,

distance is the total ground that you covered. If you started at point a, walked ten feet to point b, then turned around and walked 13 feet to point c, your total distance would be 10 + 13 = 23 feet

using the same example, your displacement is only how far away you are from the starting point. So point b doesnt matter, because you end up passing through point a again (I hope that made sense :o) and the magnitude of your displacement would be 3 feet

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Help me with this please

Alex787 [66]

Let's use the given equation, F = ma, to find out the force of each of the objects given.

A) F = 5 x 10 = 50 N

B) F = 5 x 20 = 100 N

C) F = 20 x 4 = 80 N

D) F = 20 x 3 = 60 N

The object with the greatest force is object B, with a force of 100 N.

Hope this helps! :)

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4 years ago

Read 2 more answers

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3 years ago

A + 8 μC charge lies 4 m to the left of a - 10 μC charge. A - 12 μC charge lies 8 m to its right. What is the resultant force on

MaRussiya [10]

Answer:

both side charges will exert force on central charge towards left so the two forces add up. Thus resultant force on centre charge is

F = 9×10^9 x 8×10^-6×10×10^-6/16

9× 10^9 × 10×10^-6×12×10^-6/64

= 9× 10^9 × 10^ -12/16 (80+30)

=6.18 × 10^-2 N

= 0.06 N

3 0

3 years ago

What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m

pychu [463]

Complete question:

A taut rope has a mass of 0.123 kg and a length of 3.54 m. What average power must be supplied to the rope to generate sinusoidal waves that have amplitude 0.200 m and wavelength 0.600 m if the waves are to travel at 28.0 m/s ?

Answer:

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

Explanation:

Velocity = Frequency X wavelength

V = Fλ ⇒ F = V/λ

F = 28/0.6 = 46.67 Hz

Angular frequency (ω) = 2πF = 2π (46.67) = 93.34π rad/s

Average power supplied to the rope will be calculated as follows

$P_{avg} =\frac{1}{2} \mu \omega^2 A^2 V$

where;

ω is the angular frequency

A is the amplitude

V is the velocity

μ is mass per unit length = 0.123/3.54 = 0.0348 kg/m

$P_{avg} =\frac{1}{2} ( 0.0348)(93.34 \pi )^2 (0.2)^2 (28)$ = 1676.159 watts

The average power supplied to the rope to generate sinusoidal waves is 1676.159 watts.

6 0

3 years ago

A plane has a mass of 360,000 kg takes-off at a speed of 300 km/hr. i) What should be the minimum acceleration to take off if th

melomori [17]

Answer:

i) the minimum acceleration to take off is 22500 km/h²

ii) the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) required force that the engine must exert to attain acceleration is 625 kN

Explanation:

Given the data in the question;

mass of plane m = 360,000 kg

take of speed v = 300 km/hr = 83.33 m/s

What should be the minimum acceleration to take off if the length of the runway is 2.00 km

from Newton's equation of motion;

v² = u² + 2as

we know that a plane starts from rest, so; u = 0

given that distance S = 2 km

we substitute

(300)² = 0² + ( 2 × a × 2 )

90000 = 4 × a

a = 90000 / 4

a = 22500 km/h²

Therefore, the minimum acceleration to take off is 22500 km/h²

ii) At this acceleration, how much time would the plane need from starting to takeoff.

from Newton's equation of motion;

v = u + at

we substitute

300 = 0 + 22500 × t

t = 300 / 22500

t = 0.0133 hrs

Therefore, the required time needed by the plane from starting to takeoff is 0.0133 hrs

iii) What force must the engines exert to attain this acceleration

we know that;

F = ma

acceleration a = 22500 km/hr² = 1.736 m/s²

so we substitute

F = 360,000 kg × 1.736 m/s²

F = 624960 N

F = 625 kN

Therefore, required force that the engine must exert to attain acceleration is 625 kN

5 0

3 years ago