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IceJOKER [234]
3 years ago
9

Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic

field lines. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
Physics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Explanation:

The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by

F=ILB sin \theta (1)

where I is the current, L the length of the wire, B the strength of the magnetic field, \theta the angle between the direction of the field and the direction of the current.

Also, B, I and F in the formula are all perpendicular to each other. (2)

According to eq.(1), we see that the statement:

<em>"The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.</em>"

is correct, because when the current is perpendicular to the magnetic field, \theta=90^{\circ}, sin \theta = 1 and the force is maximum.

Moreover, according to (2), we also see that the statements

<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "</em>

<em>"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "</em>

because F (the force) is perpendicular to both the magnetic field and the current.

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The question involves the knowledge of kinematics and dynamics. The answers are;

a) Time taken to stop the car = 10 s

b) The operation that slows the car is Friction

c)  The size of the force =  1200 N

<h3>What is Deceleration ?</h3>

Deceleration is the opposite of acceleration. When an object is going to rest, it will be decelerating and the final velocity will be equal to zero.

Given that the driver of a car moving at 15 m/s along a straight level road applies the brakes. The car decelerates at a steady rate of 3/2 m/s²

a) How long does the car take to stop can be found by using the formula

v = u - at

Where

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Substitute all the parameters into the formula

0 = 15 - 1.5t

1.5t = 15

t = 15/1.5

t = 10 s

b) The description of the operation that slows the car down after the brake pedal is pressed is simply friction.

c) If the mass of the car is 800. The size of the force slowing the car down will be F = ma

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