1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lorasvet [3.4K]
3 years ago
13

Action potentials _______.(A) are only found at the axon hillock and along the axon.(B) Two of the answers are correct.(C) are v

ery small changes in the membrane potential of the cell body or dendrites.(D) can travel long distances but get weaker the father they go.(E) can be either depolarizing or hyperpolarizing during their initial phase.
Physics
1 answer:
MAXImum [283]3 years ago
4 0

Answer:

A

Explanation:

Action potentials are generated at axon hillock because it contains higher density of Na+ channels.From here it is conducted down the axon with equal intensity. It initially depolarizes then polarizes, the order is strict. However, its not affected by the distance they travel.

You might be interested in
A ball is thrown straight up. It passes a 2.00-m-high window 7.50 m off the ground on its path up and takes 0.312 s to go past t
marta [7]

Answer:

Explanation:

Given that

The window height is 2m

And the window is 7.5m from the ground

Then the total height of the window from the ground is 7.5+2=9.5m

It takes the ball 0.32sec travelled pass the window.

When the ball get to the window, it has an initial velocity (u') and when it gets to the top of the window it has a final velocity ( v')

Now using the equation of free fall during this window travels

S=ut-½gt² against motion.

S=2, g=9.81, t=0.32sec

Then,

S=u't-½gt²

2=u'×0.32-½×9.81×0.32²

2=0.32u'-0.5023

2+0.5032=0.32u'

Then, 0.32u'=2.5032

u'=2.5032/0.32

u'=7.82m/s

This is the initial velocity as the ball got the the window

Now, let analyse from the window bottom to the ground which is a distance of 7.5m

Using the equation of free fall again

v²=u²-2gH

In this case the final velocity (v) is the velocity when the ball reach the bottom of the window i.e u'=7.82m/s,

While u is the original initial velocity from the throw of the ball

Then,

u'²=u²-2gH

7.82²=u²-2×9.81×7.5

61.146=u²-147.15

61.146+147.15=u²

Then, u²=208.296

So, u=√208.296

u=14.43m/s

The initial velocity of the ball form the throw is 14.43m/s

6 0
3 years ago
The severity of a fall depends on your speed when you strike the ground. All factors but the acceleration from gravity being the
Diano4ka-milaya [45]

Answer:

<em>The object could fall from six times the original height and still be safe</em>

Explanation:

<u>Free Falling</u>

When an object is released from rest in free air (no friction), the motion is completely dependant on the acceleration of gravity g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy of

U=m.g.h

When the object strikes the ground, all the mechanical energy (only potential energy) becomes into kinetic energy

\displaystyle K=\frac{1}{2}m.v^2

Where v is the speed just before hitting the ground

If we know the speed v is safe for the integrity of the object, then we can know the height it was dropped from

\displaystyle m.g.h=\frac{1}{2}m.v^2

Solving for h

\displaystyle h=\frac{m.v^2}{2mg}=\frac{v^2}{2g}

If the drop had occurred in the Moon, then

\displaystyle h_M=\frac{v_M^2}{2g_M}

Where hM, vM and gM are the corresponding parameters on the Moon. We know v is the safe hitting speed and the gravitational acceleration on the Moon is g_M=1/6 g

\displaystyle h_M=\frac{v^2}{2\frac{1}{6}g}

\displaystyle h_M=6\frac{v^2}{2g}=6h

This means the object could fall from six times the original height and still be safe

6 0
4 years ago
PLEASE HELP (100)
morpeh [17]

Answer:

The work done will be W=55.27\: J

Explanation:

The work equation is given by:

W=F\cdot x

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

F_{x-direction}=mgsin(28)

Therefore, the work done will be:

W=mgsin(28)*3

W=4*9.81*sin(28)*3

W=55.27\: J

I hope it helps you!

3 0
3 years ago
Heres some earned points
egoroff_w [7]

Answer:

what do you mean by that.

5 0
3 years ago
Read 2 more answers
In the early 1900's ____
Korvikt [17]

Answer:

Henry Ford

Explanation:

he built the first ford

7 0
3 years ago
Other questions:
  • A person drops a brick from the top of a building. The height of the building is 400 m and the mass of the brick is 2.00 kg. Wh
    12·1 answer
  • The index of refraction of a material medium must be greater than 1. true false
    13·1 answer
  • An electric field can be created by a single charge or a distribution of charges. The electric field a distance from a point cha
    9·1 answer
  • A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
    7·1 answer
  • Which kind of star is most likely to be part of the spheroidal population?
    6·1 answer
  • You and your friends find a rope that hangs down 11 m from a high tree branch right at the edge of a river. You find that you ca
    11·1 answer
  • Trafegando por uma avenida com velocidade constante de 54km/h, num dado instante, o motorista percebe o sinal vermelho à sua fre
    15·1 answer
  • The diagram shows the flow of water through a hydroelectric power station. The falling water
    8·1 answer
  • What color is reflected off of most plant leaves?
    5·2 answers
  • The range of diameters and luminosities displayed by elliptical galaxies is ____.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!