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Ugo [173]
2 years ago
6

Solve using the Quadratic Formula:

Mathematics
1 answer:
Advocard [28]2 years ago
6 0

A. - 7x² + 7x + 1 + 8 = 0

- 7x² + 7x + 9 = 0

x = - b ± √b² - 4ac / 2a

= - 7 ± √7² - 4 (-7) (9) / 2 (-7)

= - 7 ± √49 + 252 / - 14

= - 7 ± √ 301 / - 14

x = - 7 + 17.349 / - 14 x = - 7 - 17.349 / - 14

= 10.349 / - 14 = - 24.349 / - 14

= - 0.739 = - 1.739

B. 8x² - 5x² + 6x + 1 = 0

3x² + 6x + 1 = 0

x = - b ± √b² - 4ac / 2a

= - (-5) ± √-5² - 4 (3) (1) / 2 (3)

= 5 ± √25 - 12 / 6

= 5 ± √ 13 / 6

x = 5 + 3.606 /6 x = - 5 - 3.606 / 6

= 8.606/6 = - 8.606/6

= 1.434. = - 1.434

please re-check the answers hope this helps

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Answer:

9) \$1236.27\,10)\,\$6451.07\, 11)\,\$10,152.87 \,12)\,\$907.95 \,13)\,\$4957.69

Step-by-step explanation:

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A=P(1+\frac{r}{n})^{nt} ⇒ Amount (A), Principle (P), rate (r) in decimal form, number of compoundings (n) a year and t, in year or its fractions.

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=1200(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A=\$1236.27

10) Aubrey Daniel's case:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=5725(1+\frac{0.04}{4})^{4*3}\Rightarrow A\approx \$6451.07

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A=P(1+\frac{r}{n})^{nt}\Rightarrow A=9855(1+\frac{0.06}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$10,152.87

12) Simpson's. For semiannual n=2

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13) Jana Lacey amount:

A=P(1+\frac{r}{n})^{nt}\Rightarrow A=4860(1+\frac{0.04}{4})^{4*\frac{1}{2}}\Rightarrow A\approx \$4957.69

6 0
3 years ago
Question 6
marin [14]

Answer:

18 miles per hour is an outlier

the outlier decreases the mean speed

Step-by-step explanation:

the low number of 18 is way different from the other numbers being in the 30's and 40's

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8 0
3 years ago
Please help me with this geometry problem. :)
Reika [66]

Answer:

See below

Step-by-step explanation:

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6 0
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8 0
3 years ago
What is the completely factored form of f(x)=x3+5x2+4x−6?
Gre4nikov [31]
f(x)=x^3+5x^2+4x-6
f(-3)=(-3)^3+5(-3)^2+4(-3)-6=0\implies x+3\text{ is a factor of }f(x)

Synthetic division yields

-3  |  1   5   4   -6
.    |      -3  -6    6
- - - - - - - - - - - - -
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which translates to

\dfrac{x^3+5x^2+4x-6}{x+3}=x^2+2x-2

with remainder 0. Now by the quadratic formula,

x^2+2x-2=0\implies x=\dfrac{-2\pm\sqrt{2^2-4(1)(-2)}}2=-1\pm\sqrt3

and so

f(x)=x^3+5x^2+4x-6=(x+3)(x-(-1+\sqrt3))(x-(-1-\sqrt3))
3 0
3 years ago
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