0.66, 1, 2.5, 3, 4, 5, 23
Explanation
The shaded area represents a segment. This can be solved with the formula below;
Since the triangle is an equilateral triangle, it implies that the angle subtended at the centre is 60 degrees. Also, the given radius is 7 cm
![\begin{gathered} =7^2(\frac{60}{360}\times3.14-\frac{1}{2}\times\sin 60)^{}_{} \\ =49(\frac{3.14}{6}-\frac{\sqrt[]{3}}{4}) \\ =4.43\operatorname{cm}^2 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%3D7%5E2%28%5Cfrac%7B60%7D%7B360%7D%5Ctimes3.14-%5Cfrac%7B1%7D%7B2%7D%5Ctimes%5Csin%2060%29%5E%7B%7D_%7B%7D%20%5C%5C%20%3D49%28%5Cfrac%7B3.14%7D%7B6%7D-%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B4%7D%29%20%5C%5C%20%3D4.43%5Coperatorname%7Bcm%7D%5E2%20%5Cend%7Bgathered%7D)
Answer:
Sid walked 6 miles, which is 3/5 of the total distance.
Divide 6 with 3
6/3 = 2
2 miles is the walking distance for 1/5
Multiply 5 to both sides
2 (x 5) = 1/5 (x 5)
10 = 1
The total distance is 10 miles
hope this helps
Twenty percent of $35 is 0.20($35) = $7. The discount is $7.
The solution for the problem is:
I will first get the first five terms so that I could easily locate the third term of this problem:So, substituting the values:
T(1) = 1^2 = 1T(2) = 2^2 = 4T(3) = 3^2 = 9T(4) = 4^2 = 16T(5) = 5^2 =25
So the third terms is T(3) = 3^2 = 9
