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-Dominant- [34]
3 years ago
7

Consider the following functions. f={(−4,−1),(1,1),(−3,−2),(−5,2)} and g={(1,1),(2,−3),(3,−1)}: Find (f−g)(1).

Mathematics
1 answer:
fenix001 [56]3 years ago
7 0

Answer:

0

Step-by-step explanation:

Subtraction of functions has the property:

  • (f−g)(1) = f(1) - g(1)

f={(−4,−1),(1,1),(−3,−2),(−5,2)}  has (1,1) means that f maps 1 to 1, therefore f(1) = 1

g={(1,1),(2,−3),(3,−1)}  has (1,1), means that g maps 1 to 1, therefore g(1)=1

As a Result, since (f−g)(1) = f(1) - g(1), we have (f−g)(1) = 1-1=0

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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

Given: f(x) = 4x^2 \text { and } g(x) = x+1

To find: (f_\circ g)(x)

As we know it is composition function which means that  g(x) function is in f(x) function.

So we have

(f_\circ g) (x) =  f[g(x)]

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Now substitute the value of g(x) we get

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3 years ago
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schepotkina [342]

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