Answer:
The volume of the tumor experimented a decrease of 54.34 percent.
Step-by-step explanation:
Let suppose that tumor has an spherical geometry, whose volume (
) is calculated by:
Where 
is the radius of the tumor.
The percentage decrease in the volume of the tumor (
) is expressed by:
Where:
- Absolute decrease in the volume of the tumor.
- Initial volume of the tumor.
The absolute decrease in the volume of the tumor is:
The percentage decrease is finally simplified:
![\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7BR_%7Bf%7D%7D%7BR_%7Bo%7D%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
Given that 
and 
, the percentage decrease in the volume of tumor is:
![\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%](https://tex.z-dn.net/?f=%5C%25V%20%3D%20%5Cleft%5B1-%5Cleft%28%5Cfrac%7B0.77%5Ccdot%20R%7D%7BR%7D%5Cright%29%5E%7B3%7D%20%5Cright%5D%5Ctimes%20100%5C%2C%5C%25)
The volume of the tumor experimented a decrease of 54.34 percent.
Answer:
The correct answer is A -6/17
Answer:
What do think the answer is cause I don't know
The dad had 6 more hours remaining to drive
Answer: 1/3
Explanation:
1/12 of the squad are suspended:
1/12 x 24 = 24/12 = 2
So 2 player are suspended
24 - 2 = 22 player
And some are injured leaving 14 left to play:
22 - 14 = 8 players injured
So 8/24 is the fraction of injured player.
But 8/24 = 1/3 so we can say 1/3 of the whole squad are injured.
