You basically use the formula height*base/2 to find the area of the triangle. For instance, let's say a is your chosen base, which has a length of 7. You then use the pythagorean theorem of the right triangle (which is formed by splitting the triangle in half), which is a^2+b^2=c^2, and you substitute half your base for a and the other length (8) for c, which is the hypotenuse of the triangle. Note how this is all being done to find "b", which is the height of the triangle, which will then help you substitute all of your known values into the area formula of a triangle to answer your question. I'm not sure if b=141 degrees would have an impact on this question, but I hope this helped you in some way.
Answer:
Step-by-step explanation:
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First we will change them on the same denominator which will be 12. If we do something to the denominator we must do the same to the numerator so :
For 1/3 we get 4/12 because (1/3)*4 = 4/12
And for 2/3 we get 8/12 because (2/3)*4 = 8/12
So 1/3 is the smaller fraction, 7/12 is in the middle and 2/3 is the bigger fraction.
Answer: just follow these simple steps!
Step-by-step explanation:
1. Estimate the quotient.
2. Perform the division. Remember to place a zero in the quotient when the divisor is larger than the dividend. ...
3. Compare your estimate with your quotient to verify that the answer makes sense.
The general direction that Lin walked from the gym to his house is; B: Lin walked southwest, creating an obtuse triangle.
<h3>How to interpret distance bearing?</h3>
We are given;
Distance between the lecture hall and gym = 910 feet.
Distance between the gym and Lin apostrophe's house = 615 feet.
Distance between the lecture hall and Lin apostrophe's house = 651 feet.
Now, since this 3 distances form a triangle and the 3 distances are unequal, then we can call it an obtuse triangle since he walked west and then walked northwest.
Now, since he walked back to his house from the gym, we can say that he walked southwest if we picture the bearing of his first two directions.
Read more about Distance Bearing at; brainly.com/question/22719608
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