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3 years ago

5

The puppy needs to catch a train that is moving at 8 km/h. She is 100m away and running at 10 km/h. How far will the train have

traveled before the puppy is able to jump on?

1 answer:

Montano1993 [528]3 years ago

6 0

Answer:

400 meters

0 meters if the puppy can jump really really far ha ha ....

P = 10000x - 100

T = 8000x

10000x - 100 = 8000x

2000x = 100

x = 1/20 hr

60/20 = 3 minutes

Step-by-step explanation:

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Let x be the number of successes throughout n independent repetitions of a random experiment having probability of success p=1/4

Llana [10]

To answer problems like this you have to use binomial:

P (x > 1) = 1 – p (0 < x < 1) > .7

So:

1 – p (0) – p (1) > .7

1 – (3/ 4) ^n – (3/ 4) ^n (n – 1 ) (1/ 4) > .7

Therefore n > 5.185, and the smallest value of n so that we can satisfy the given condition is 6 (rounded up)

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6 0

4 years ago

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

4 years ago

Three apples weigh about a pound about how much would one apple cost round to the nearest tenth

7nadin3 [17]

3 apples weigh 1 lb.....so 1 apple would weigh 1/3 = 0.3 lbs

5 0

3 years ago

It takes water in minutes to get to his friend's house. If he travels to his friends house 8 days in a row, taking a total of 18

rewona [7]

Answer:

It takes him 23 minutes a day.

Step-by-step explanation:

To find this, we simply take the number of minutes in total and divide by the number of times he does it.

Amount = Total time/Amount of times

Amount = 184/8

Amount = 23

4 0

4 years ago

PLEASE HELP ME!!!!!!!!!!!

marta [7]

First divide them all then multiply them and then add it up it should equal 50

3 0

3 years ago