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3 years ago

Factor Completely 5v^2-5v-100

Mathematics

2 answers:

timofeeve [1]3 years ago

6 0

Answer:

5(v-5)(v+4)

Step-by-step explanation:

We have given a expression.

5v²-5v-100

We have to calculate the factor of given expression.

As we know that 5 is multiple of 5 and 100.

taking 5 common from given expression, we have

5(v²-v-20)

Splitting the middle term of given expression, we have

5(v²-5v+4v-20)

Making groups and taking common, we have

5(v(v-5)+4(v-5))

Taking v-5 as common, we have

5(v-5)(v+4) which is the answer.

bogdanovich [222]3 years ago

4 0

$5 {v }^{2} - 5v - 100 \\ = 5( {v}^{2} - v - 25) \\ = 5({v}^{2} + 4v - 5v - 20) \\ = 5[v(v + 4) - 5(v + 4)] \\ = 5(v - 5)(v + 4)$

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Y=log(x-3) what would be the base?

timurjin [86]

By definition, if :

$a^y = b$

$y = log_a b$

We highlight the following elements:

a = Base of the logarithm;
b = logarithmand or antilogarithm
y = logarithm

Therefore:

Note that since the base was not specified, we know that it is equal to 10.

$y = log_a b$
$y = log_{10} (x-3)$
$10^y = (x-3)$

Answer:

Base of the logarithm = 10

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3 years ago

Which transformations have been applied to the graph of f(x) = x2 to produce the graph of g(x) = –5x2 + 100x – 450? Select three

RSB [31]

Answer:

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

Step-by-step explanation:

we have

$f(x)=x^{2}$

This is a vertical parabola open upward

The vertex is a minimum

The vertex is the origin (0,0)

$g(x)=-5x^{2}+100x-450$

This is a vertical parabola open downward

The vertex is a maximum

The first thing to note is that fx) is a parabola that opens up and g(x) opens down, so a reflection across the x-axis must have been applied.

Find the vertex of g(x)

Convert to vertex form

$g(x)=-5x^{2}+100x-450$

Complete the square

$g(x)=-5(x^{2}-20x)-450$

$g(x)=-5(x^{2}-20x+100)-450+500$

$g(x)=-5(x^{2}-20x+100)+50$

$g(x)=-5(x-10)^{2}+50$

The vertex is the point (10,50)

To translate the vertex of (0,0) to (10,50)

The rule of the translation is

(x,y) ------> (x+10,y+50)

That means ----> The translation is 10 units at right and 50 units up

therefore

The transformations are

The graph of f(x) is shifted up 50 units

The graph of f(x) is shifted right 10 units

The graph of f(x) is reflected over the x-axis

5 0

3 years ago

Read 2 more answers

Please help:(

Vladimir [108]

Answer c would be the answer hope it helps

Step-by-step ex planation:

7 0

2 years ago

In February, Ronald. Read a book that was 98 pages long. In March, he read a book that was 124 pages long. In April, he read a b

tester [92]

Answer:

430

Step-by-step explanation:

You add 98+124 which is 222 then add it plus 208 which is 430

7 0

3 years ago

Read 2 more answers

Y=4x-6 and passes through point 8,12

umka2103 [35]

Answer:

Slope of required line if both lines are parallel: y=4x-20

Slope of required line if both lines are perpendicular: y=-1/4x+14

Step-by-step explanation:

We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)

Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.

If Both lines are parallel the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are parallel there slopes are same

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=4

Now finding y-intercept

Using slope m=4 and point (8,12) we can find y-intercept

$y=mx+b\\12=4(8)+b\\12=32+b\\b=12-32\\b=-20$

y-intercept of new line is: b=-20

Equation of required line having slope m=4 and y-intercept b=-20 is

$y=mx+b\\y=4x-20$

If Both lines are perpendicular the equation of new line will be:

We need to find slope and y-intercept to write equation of new line.

When lines are perpendicular there slopes are opposite of each other

So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)

Slope of new line is: m=-1/4

Now finding y-intercept

Using slope m=-1/4 and point (8,12) we can find y-intercept

$y=mx+b\\12=-\frac{1}{4} (8)+b\\12=-2+b\\b=12+2\\b=14$

y-intercept of new line is: b=14

Equation of required line having slope m=-1/4 and y-intercept b=14 is

$y=mx+b\\y=-\frac{1}{4} x+14$

8 0

2 years ago