The benchmarks are: 0, 0.25, 0.50, 0.75 and 1.
2. 81 → 2.75
+
3.73 → 3.75
------------
2.75 + 3.75 = 6.50
Answer:
The number of once is 9.1
The number of hundreds is 8.9
Step-by-step explanation:
Given as :
The total of digits having ones and hundreds = 900
The sum of digits = 18
Let The number of ones digit = O
And The number of hundreds digit = H
So, According to question
H + O = 18 .........1
100 × H + 1 × O = 900 ........2
Solving the equation
( 100 × H - H ) + ( O - O ) = 900 - 18
Or, 99 H + 0 = 882
Or , 99 H = 882
∴ H = 
I.e H = 8.9
Put the value of H in eq 1
So, O = 18 - H
I.e O = 18 - 8.9
∴ O = 9.1
So, number of once = 9.1
number of hundreds = 8.9
Hence The number of once is 9.1 and The number of hundreds is 8.9
Answer
<span>y=x^2+5x+6
y=4x+12
Solution = (-3,0) and (2,20)
</span><span>y=x^2-3x-1
y=8x-1
Solution = (0,-1) and (11,87)</span>
Answer:
1.5 and 4.4
Step-by-step explanation:
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Answer:
19
Step-by-step explanation:
