Can someone plz explain how to do this?

Jean can pack 5 cartons in 15 minutes. Which expression can be used to show the number of cartons Jean can pack in x hours? Grou

nadezda [96]

Answer: 20x

Step-by-step explanation:

First we should note that 60 minutes = 1 hour. Therefore, 15 minutes = 15/60 = 1/4 hour

Since Jean can pack 5 cartons in 1/4 hours, the number of carton that he can pack in one hour will be:

= 5 ÷ 1/4

= 5 × 4

= 20 cartons.

Therefore, to get the number of cartons that Jean can pack in x hours, we will multiply 20 by x. This will be:

= 20 × x

= 20x

6 0

3 years ago

Helena lost her marbles. But then she found them and put them in 4 bags with mm marbles in each bag. She had 3 marbles left over

77julia77 [94]

Answer:

4m +3 marbles does Helena have in all.

Step-by-step explanation:

Here, m represents the marble in each bag.

She put them in 4 bags with m marbles in each bag.

In each bag she have m marbles

then, in 4 bag she have 4m marbles

⇒total number of marbles= 4m

Since, she had 3 marbles left over.

⇒She have total number of marbles = 4m + 3

Therefore, 4m +3 marbles does Helena have in all.

8 0

3 years ago

Read 2 more answers

Let s(t) = 36 − t. find the equation of the tangent line to s(t) when t = 0.

tatiyna

When t = 0 the point on the graph is (0,36). Your equation is just a line and always has the same tangent line so your equation is the same s = 36 - t.

5 0

3 years ago

Divide. -4 1/3 divided by 2 3/5

Alexus [3.1K]

The answer is: -1.66666666667 to be exact

6 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

8 0

4 years ago

Can someone plz explain how to do this?​

Can someone plz explain how to do this?