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DaniilM [7]
2 years ago
5

Can someone plz explain how to do this?​

Mathematics
1 answer:
andre [41]2 years ago
5 0
Subtract y
3x - y + 5 = 0
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Solve the equation<br><br> 1 . J + -2 = -22
olganol [36]

J + -2 = -22

Adding a negative number changes the equation to subtract ruin:

J - 2 = -22

Now add 2 to both sides to get the answer:

J = -20

7 0
3 years ago
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What's the negative reciprocal of 5? Question 12 options: A) 1∕5 B) –5 C) –1∕5 D) 5
levacccp [35]

Answer:

\huge\boxed{C)\ -\dfrac{1}{5}}

Step-by-step explanation:

The reciprocal of 5: \dfrac{1}{5}

The negative reciprocal of 5: -\dfrac{1}{5}

7 0
2 years ago
What two numbers multiply to equal -27 but adds up to equal -6
kkurt [141]

Answer:

-9 and 3

Step-by-step explanation:

as -9×3= -27

and

-9+3= -6

4 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
3 years ago
. <br> Solve using traditional division: 3,385 31.<br> 109 R6<br> 1009<br> 108 R 37<br> 109
dimulka [17.4K]

Answer:

109r6

Step-by-step explanationi got it

7 0
3 years ago
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