Step 1: 1/10 + 1/10 = 2/10
Step 2: 4/5 - 2/10
GCF: multiply both sides of 4/5 by 2 = 8/10
Step 3: 8/10 - 2-10 = 6/10
ANSWER: C <span>fraction 6 over 10, because fraction 4 over 5 minus 2 times fraction 1 over 10 equals fraction 4 over 5 minus fraction 2 over 10 </span>
Answer: D, When the constants are perfect squares.
Step-by-step explanation:
the “best” method whenever the quadratic equation only contains x2 terms. That implies no presence of any x term being raised to the first power somewhere in the equation.
Hopefully this helps!
Answer:
<u>x= 4 2/3 </u><em><u>OR</u></em><u> 14/3 </u><em><u>OR</u></em><u> 4.6... –– 4 2/3 and 4.6... are the simplest form.</u>
Step-by-step explanation:
Your original equation is -192 = -6 (6x - 4):
1. -192 = -6 (6x - 4)
Use distributive property and multiply: -6 x 6x = -36x and -6 x -4 = 24:
2. -192 = -36x + 24
We now move the +24 onto the other side of the equation, -192. Add 24 onto -192 and since we're moving the 24 on the left side of the equation, 24 will removed, so -24 on the right side of the equation:
3. -192 + 24 = -36x + 24 - 24
Divide both sides of the equations by -36 to get "x" by itself:
4. -168 / -36 = -36x / -36
Simplify the fraction of 24/36 by 12:
5. 4 24/36 = 4 2/3 or 14/3 or 4.6... = x
<u>4 2/3, 14/3, 4.6... = x</u>
Answer:
1. x = 12
2. 3∛4 feet.
Step-by-step explanation:
1. We are given the equation of x as
and we have to find the extraneous solution of the equation.
Now,
............. (1)
⇒ 
Squaring both sides we get,
⇒ x - 3 = 81 - 18x + x²
⇒ x² - 19x + 84 = 0
⇒ x² - 12x - 7x + 84 = 0
⇒ (x - 12)(x - 7) = 0
⇒ x = 12 or 7.
Now, putting x = 12 in the equation (1) we get,

Again, putting x = 7 in the equation (1) we get,

Therefore, x = 12 is an extraneous solution of this equation. (Answer)
2. The volume of a cube with side lengths a ft. is given to be 108 ft³.
So, a³ = 108
⇒ a = 3∛4 feet.
Therefore, the length of the sides of the cube are each 3∛4 feet. (Answer)