Answer:
The company should take a sample of 148 boxes.
Step-by-step explanation:
Hello!
The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.
They estimated a "pilot" proportion of p'=0.20
And using a 90% confidence level the CI should have a margin of error of 2% (0.02).
The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"
[p' ±
]
Where
p' is the sample proportion/point estimator of the population proportion
is the margin of error (d) of the confidence interval.

So






n= 147.28 ≅ 148 boxes.
I hope it helps!
C= Colorado B= Boston
C + B = 464
C = 1.2B
Substitute the known value of C from the second equation into the first
C + B = 464
(1.2B) + B = 464
2.2B = 464
Divide each side by 2.2
B = 210.9, rounded to 211 (it's asking for days, not partial days, so round)
If Boston has 211 days of sunshine , then Colorado Springs has 1.2 times that amount. 211 * 1.2 = 253.2 (rounded to 253)
Verification
211 + 253 = 464
So first you would put these over a common denominator which is 96. You get this by multiplying by 9 and what you do to the denominator you must do to the numerator so you then get 45/96 and 63/96. Pelicans=45/96. Woodpeckers=63/96
Answer:
9
Step-by-step explanation:
Answer:
it is 1
Step-by-step explanation: