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galben [10]
3 years ago
13

What is the difference between 21.25-1.509

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
7 0

Answer:

19.741

Step-by-step explanation:

When subtracting decimals line up the decimals and then add 0s to the end to make it work. SO instead of

21.25

-1.509

___________

It would be

21.250

- 1.509

______________

Solve the subtraction problem like you normally would. THen drop the decimal down so it lies up with the others.

21.250

- 1.509

______________

19.741

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How do i find the slope
Elodia [21]

Hi, I'm happy to help!

To find the slope, you need to use the slope formula, where m is the slope:

<u>m=</u>\frac{y_{2}-y_{1 } }{x_{2} -x_{1} }<u></u>

Slope means rise over run, or how much the line rises per the amount the line moves forward. This equation shows the movement from the y points to show <u>rise</u>, over the difference in the x points to show <u>run</u>.

Now, to find the slope we insert our values, starting with our second y point:

<u>m=</u>\frac{2-y_{1 } }{x_{2} -x_{1} }<u></u>

Now insert our first y point:

<u>m=</u>\frac{2-4 }{x_{2} -x_{1} }<u></u>

Now we insert our second x point:

<u>m=</u>\frac{2-4 }{-3 -x_{1} }<u></u>

And finally our first x point:

<u>m=</u>\frac{2-4 }{-3 -3 }

Now, we solve:

<u>m=</u>\frac{-2 }{-6}

So, our slope is -2/-6, to simplify it, we remove both negatives because they cancel each other out.

<u>m=</u>\frac{2 }{6}

Now, we simplify our fraction by dividing the top and bottom by 2:

<u>m=</u>\frac{1}{3}<u></u>

So, our slope is 1/3. This means that for every 1 unit the line rises, it goes to the right 3 units. The y-intercept is where the line hits the y axis.

If the question is asking for slope intercept form for the equation, you use y=mx+b

y represents any y coordinate on your line, m represents your slope (1/3), x represents any x coordinate on your line, and b represents your y-intercept (3).

If you were to insert these values, you would get:

y=\frac{1}{3}x+3

You use this to find what a y coordinate would be so you can draw your line.

For the next equation we do the same thing:

<u>m=</u>\frac{y_{2}-y_{1 } }{x_{2} -x_{1} }<u></u>

Insert our values:

<u>m=</u>\frac{4-1}{2-(-4)}<u></u>

Get rid of the double negative:

<u>m=</u>\frac{4-1}{2+4}<u></u>

Solve:

<u>m=</u>\frac{3}{6}<u></u>

Simplify:

<u>m=</u>\frac{1}{2}

Now that we know our slope, let's plug it in to our slope intercept form equation.

y=\frac{1}{2}x+3

I hope this was helpful! Keep learning! :D

5 0
3 years ago
One tank is filling at a rate of 4/5 gallon per 1/2 minute. A second tank is filling at a rate of 7/8 gallon per 1/2 minute. Whi
telo118 [61]

Answer:

The second tank.

Step-by-step explanation:

Since both filling up at the same rate, all you would have to do is multiply the gallons.

4/5 multiplying top and bottom by 8 is 32/40

7/8 multiplying top and bottom by 5 is 35/40

8 0
3 years ago
Read 2 more answers
Which letter on the diagram below represents the name of the circle?
Alik [6]

Answer:  (b) A

<u>Step-by-step explanation:</u>

A: the center of the circle

B: the diameter of the circle

C: the radius of the circle

D: <em>not sure, could be the perimeter</em>

<em />

Circles are named by their center, so this is named "Circle A".

6 0
4 years ago
Read 2 more answers
SOMEONE PLEASEEEE HELPPPP
andrew11 [14]

Answer:

The triangles are not similar

Step-by-step explanation:

6 0
3 years ago
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

=<em> 6.2</em>

(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
3 years ago
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