2 years ago

A No solution

Mathematics

2 answers:

malfutka [58]2 years ago

8 0

One solution I beleve

Anvisha [2.4K]2 years ago

6 0

I think Itsss B
—————————-

You might be interested in

(−t 4 −5t 3 −10t 2 )+(9t 3 +3t 2 −1)

klemol [59]

Answer:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

Step-by-step explanation:

Given the expression

$\left(-t^4\:-5t^3\:-10t^2\:\right)+\left(9t^3\:+3t^2\:-1\right)$

Remove parentheses: (a)=a

$=-t^4-5t^3-10t^2+9t^3+3t^2-1$

Group like terms

$=-t^4-5t^3+9t^3-10t^2+3t^2-1$

Add similar elements

$=-t^4-5t^3+9t^3-7t^2-1$ ∵ $-10t^2+3t^2=-7t^2$

Add similar elements

$=-t^4+4t^3-7t^2-1$ ∵ $-5t^3+9t^3=4t^3$

Thus, the equivalent expression in simplified form:

$\left(-t^4-5t^3-10t^2\right)+\left(9t^3+3t^2-1\right)=-t^4+4t^3-7t^2-1$

4 0

2 years ago

Choose what the expressions below best represent within the context of the word problem. The tens digit of a number is twice the

Usimov [2.4K]

2x + x = 12
=> x =12/3 =4
so, original number is 84.

6 0

3 years ago

Find the arc length of the partial circle. length is 1. **See attached photo**

KatRina [158]

Arc length of the quarter circle is 1.57 units.

Solution:

Radius of the quarter circle = 1

Center angle (θ) = 90°

To find the arc length of the quarter circle:

$$\text{Arc length}=2 \pi r\left(\frac{\theta}{360^\circ}\right)$

$$=2 \times 3.14 \times 1\left(\frac{90^\circ}{360^\circ}\right)$

$$=2 \times 3.14 \times 1\left(\frac{1}{4}\right)$

Arc length = 1.57 units

Arc length of the quarter circle is 1.57 units.

5 0

3 years ago

Help please with this question?

Aliun [14]

36/39 or 12/13 is th answer to that

4 0

2 years ago

Read 2 more answers

F(x)=x+1, g(x)=-x, and h(x)=x^2+1 find (g of)(x)

Dvinal [7]

Answer:

Step-by-step explanation:

6 0

2 years ago